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Number Game

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by zagcollins » Mon Jul 28, 2008 9:10 am
Each of the numbers w,x,y,and z is equal to either 0 or 1.What is the value of w+x+y+z?

1)w/2+x/4+y/8+z/16=11/16
2)w/3+x/9+y/27+z/81=31/81


OA is D..this is a question from GPREP...
Last edited by zagcollins on Tue Jul 29, 2008 4:34 am, edited 1 time in total.
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by harish » Mon Jul 28, 2008 10:34 am
IMO is D
Since w,x,y,z can have either 0 or 1
from (i)

Keep the denominator equal to 16
8(1) + 4(0) + 2(1) + 1(1) = 11

11 Could be acheived only when wxyz = {1011} ==> 8+2+1

So w+x+y+z=3

Similarly with (ii)
Keep the denominator equal to 81
27(1) + 9(0) + 3(1) + 1(1) = 31

So Answer is D

Whats OA???
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by ricky » Mon Jul 28, 2008 11:08 am
IMO Ans shud be D

What is OA?
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