Referencing Official Guide 12th Edition. Page 197 Q 32.
Both B and D are correct depending on how to solve the root.
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nevermind.. it was my bad :)
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sqrt[(16)(20) + (8)(32)] =
sqrt[ (2^4)(5*2^2) + (2^3)(2^5)] =
sqrt[5*2^6 + 2^8] =
sqrt[2^6(5 + 2^2)] =
sqrt[2^6]*sqrt[5 + 2^2] =
8*sqrt[9] =
8*3 =
24
You broke some rule of algebra if you got D. Solving a problem in different way must yield the same answer. How did you get D?
sqrt[ (2^4)(5*2^2) + (2^3)(2^5)] =
sqrt[5*2^6 + 2^8] =
sqrt[2^6(5 + 2^2)] =
sqrt[2^6]*sqrt[5 + 2^2] =
8*sqrt[9] =
8*3 =
24
You broke some rule of algebra if you got D. Solving a problem in different way must yield the same answer. How did you get D?
