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voodoo_child
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In the XY-Plane , is the slope of the line k equal to 0 ?
(1) The X- intercept of k is 0
(2) The y-intercept of k is 0.
Logically, OA E makes sense.
However, I need to understand what's wrong with the algebraic method. Please don't reply with an intuitive answer. There is no doubt about OA.
A
Let the equation of line be y=mx+c
1) X intercept => 0=mx+c => x=-c/m; Now if the x-intercept =0; it means that m could be either infinity or a non-zero. I believe that "Infinity/Infinity" is undefined. Hence, m will not be equal to Zero. No. This doesn't make sense. What am I missing here?
2) Y intercept => y= c =0; therefore, y=mx; Not sufficient.
1 and 2) x intercept = 0 and y-intercept = 0=> c=0 and c/m=0 => m is not equal to zero.
It's crazy, but I am a bit lost....
Thoughts?
(1) The X- intercept of k is 0
(2) The y-intercept of k is 0.
Logically, OA E makes sense.
However, I need to understand what's wrong with the algebraic method. Please don't reply with an intuitive answer. There is no doubt about OA.
A
Let the equation of line be y=mx+c
1) X intercept => 0=mx+c => x=-c/m; Now if the x-intercept =0; it means that m could be either infinity or a non-zero. I believe that "Infinity/Infinity" is undefined. Hence, m will not be equal to Zero. No. This doesn't make sense. What am I missing here?
2) Y intercept => y= c =0; therefore, y=mx; Not sufficient.
1 and 2) x intercept = 0 and y-intercept = 0=> c=0 and c/m=0 => m is not equal to zero.
It's crazy, but I am a bit lost....
Thoughts?
