I just ran across a DS problem requiring you to know whether there are more than one combination of a set of numbers that will satisfy this:
Even multiple of 3 + a multiple of 3 = 135
Is there a way to use number property to solve this?
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Multiple of 3
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nycknicks11
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Please post the whole question.
Your question can be rewritten as:
3(2a)+3(b)=135
2a+b=45 ; I'm pretty sure the question tells you positive multiples. Find out how many combinations satisfy that equation.
Your question can be rewritten as:
3(2a)+3(b)=135
2a+b=45 ; I'm pretty sure the question tells you positive multiples. Find out how many combinations satisfy that equation.
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nycknicks11
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it's literally that. yes positives and integers.
even mult. of 3 is basically multiple of 6. So I just started pluggin numbers. Just wondering if theres even a quicker way.
I also tried 2a=3(45-b) but this took longer. 45-b must be even so b must be odd. etc..
even mult. of 3 is basically multiple of 6. So I just started pluggin numbers. Just wondering if theres even a quicker way.
I also tried 2a=3(45-b) but this took longer. 45-b must be even so b must be odd. etc..
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smackmartine
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Rule: Even + Odd = Odd
Given, Even multiple of 3 + a multiple of 3 = 135
Keep it simple
case 1 :126 (Even multiple of 3) + 9(a multiple of 3) = 135
case 2 :132(Even multiple of 3) + 3(a multiple of 3) = 135
So, there can be more than one combinations that add to 135. Hope this answers your question.
Given, Even multiple of 3 + a multiple of 3 = 135
Keep it simple
case 1 :126 (Even multiple of 3) + 9(a multiple of 3) = 135
case 2 :132(Even multiple of 3) + 3(a multiple of 3) = 135
So, there can be more than one combinations that add to 135. Hope this answers your question.
Just to clarify my point.
When you have 2a+b=45 and you need to find how many combinations of positive integers are there?
just divide the 45 by 2(coefficient in front of "a"), you will find 22 ways in which the equations can work.
a can be(1,2,..,21,22)
I hope I answered your question
When you have 2a+b=45 and you need to find how many combinations of positive integers are there?
just divide the 45 by 2(coefficient in front of "a"), you will find 22 ways in which the equations can work.
a can be(1,2,..,21,22)
I hope I answered your question
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nycknicks11
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