Problem Solving

Roland2rule wrote:Two kinds of Vodka are mixed in the ratio 1:2 and 2:1 and they are sold fetching the profit 10% and 20% respectively. If the vodkas are mixed in equal ratio and the individual profit percent on them are increased by 4/3 and 5/3 times respectively, then the mixture will fetch the profit of

A. 21%
B. 23%
C. 20%
D. 18%
E. Cannot be determined
OA is c

any expert with a simple and detailed mathematical approach to solving this question.

Let's assume the following.

The profit on the first kind of vodka = x% and the profit on the second kind of vodka = y%.

Case 1: Mixing them in the ratio 1 : 2 gives the average profit equal to 10%

=> (x + 2y)/3 = 10 ---(1)

Case 2: Mixing them in the ratio 2 : 1 gives the average profit equal to 20%

=> (2x + y)/3 = 20 ---(2)

Solving (1) and (2), we get x = 30% and y = 0% (The second kind of vodka sold on no profit).

After the individual profit percent on them are increased by 4/3 and 5/3 times respectively, the profit becomes 30% x (4/3) = 40% and 0% x (5/3) = 0%, on the first and the second kinds of vodka, respectively.

If they are mixed in an equal ratio, i.e., in the ratio of 1 : 1, then the mixture will fetch an average profit of (40 + 0)/2 = 20%.

The correct answer: C

Hope this helps!

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