I have solved the first one using the alligation.I donno how to solve the second one.


Wine solution contains 3 wine and 1 water.
We are adding water to make 1/2 wine.

3(parts of wine in first solutn) 0(parts of wine in 2nd soln ie water)

1/2

0- 1/2 1/2-3

0 minus 1/2 : 1/2 -3 gives the ratio of the weights

0-1/2 : 1/2: 3 = [spoiler]1:5[/spoiler] - which is the answer.

i didn't understand the explanation

For the first problem I get B 1/3

we're told that we have a mixture that is 3/4 alcohol and 1/4 water then let's assume that we have 12 liters of mixture and therefore we have 9 liters of alcohol and 3 liters of water and we want to end up with 6 liters of alcohol and 6 liters of water.

This means that we need to remove 3 liters of alcohol. Every time you remove a liter from the mixture you're removing 3/4 liters of alcohol so
if X are the liters that we need to remove from the mixture.

3 = 3/4X then X = 4 which is 1/3 of 12.

if you want to set the equations, it would be something like this. We have to equal the fraction of alcohol to the fraction of water.

we initially have 3/4 of alcohol and we remove 3/4 of the proportion X
so the final amount of alcohol would be 3/4 - 3/4X.

we initially have 1/4 of water and we add X but at the same time we remove 1/4X so if fact we add 3/4X

setting the equations

3/4 - 3/4X = 1/4 + 3/4X --> 2/4 = 6/4X ---> X = 1/3



For the second problem I get C.

Let's say that the product costs $100.
The price for the people who pay in cash is $100
and the price for the people who pay in one month is $100 + 100*0.04/12 = 100 + 1/3 = 301/3

the ratio then is 100 / 301/3 --> 300/301 ---> 3000/3010.

Thanks mate....

The OA for q1 is b and q2 is c.