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mgmat 4

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mgmat 4

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If t and u are positive integers, what is the value of t-2u-3?

(1) t-3u-2 = 1/36

(2) t(u-1) = 1/6



qa is a


statement one renders t=1 and u as 6 but cant we account for -6 also? THis made me choose statement one as insuf.

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Are you sure that you have written the question correctly. As written the question and the answer does not make any sense. Kindly pay more attention to what you are typing.

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If t and u are positive integers, what is the value of t-2u-3?

(1) t-3u-2 = 1/36

(2) t(u-1) = 1/6


qa is a


sorry html problem

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If t and u are positive integers, what is the value of (t^-2)(u^-3)?

(1) (t^-3)(u^-2) = 1/36

(2) t(u^-1) = 1/6



pesky pc problem fixed.. thanks for the patience.


qa is a

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Where did you get the question from?
There are no integer values for t & u for which (t^-3)(u^-2) = 1/36
36 = 2*2*3*3 but the combined power of the expression is 5.

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this came from manhattan gmat question bank.

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resilient wrote:
this came from manhattan gmat question bank.
Then check the question again. you are missing something.

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i am looking at the exact same problem right now and have no clue how to move forward since there are no integers that make up 1/36. he did not type the problem wrong, it is correct. please somebody help
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Quote:
If t and u are positive integers, what is the value of (t^-2)(u^-3)?

(1) (t^-3)(u^-2) = 1/36

(2) t(u^-1) = 1/6
What is the value of (1/t²)(1/u³)?

Statement 2: t/u = 1/6.
Case 1: t=1, u=6
In this case, (1/t²)(1/u³) = (1/1²)(1/6³).
Case 2: t=2, u=12
In this case, (1/t²)(1/u³) = (1/2²)(1/12³).
Since (1/t²)(1/u³) can be different values, INSUFFICIENT.

Statement 1: (1/t³)(1/u²) = 1/36.
Case 1: t=1, u=6
This case also satisfies statement 1, since (1/1³)(1/6²) = 1/36.

No other pair of positive integers will satisfy Statement 1.
Since only Case 1 is possible, (1/t²)(1/u³) = (1/1²)(1/6³).
SUFFICIENT.

The correct answer is A.

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Last edited by GMATGuruNY on Fri Aug 10, 2018 7:50 am; edited 1 time in total

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GMATGuruNY wrote:
Quote:
If t and u are positive integers, what is the value of (t^-2)(u^-3)?

(1) (t^-3)(u^-2) = 1/36

(2) t(u^-1) = 1/6
What is the value of (1/t²)(1/u³)?

Statement 2: t/u = 1/6.
Case 1: t=1, u=6
In this case, (1/t²)(1/t³) = (1/1²)(1/6³).
Case 2: t=2, u=12
In this case, (1/t²)(1/u³) = (1/2²)(1/12³).
Since (1/t²)(1/u³) can be different values, INSUFFICIENT.

Statement 1: (1/t³)(1/u²) = 1/36.
Case 1: t=1, u=6
This case also satisfies statement 1, since (1/1³)(1/6²) = 1/36.

No other pair of positive integers will satisfy Statement 1.
Since only Case 1 is possible, (1/t²)(1/u³) = (1/1²)(1/6³).
SUFFICIENT.

The correct answer is A.
Hello Mitch,

Under case 1 "In this case, (1/t²)(1/) = (1/1²)(1/6³). " The highlighted value must be u^3.

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alanforde800Maximus wrote:
Hello Mitch,

Under case 1 "In this case, (1/t²)(1/) = (1/1²)(1/6³). " The highlighted value must be u^3.
Fixed!
Thanks for pointing out the typo.

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