• Get 300+ Practice Questions

Available with Beat the GMAT members only code

• Award-winning private GMAT tutoring
Register now and save up to \$200

Available with Beat the GMAT members only code

• Magoosh
Study with Magoosh GMAT prep

Available with Beat the GMAT members only code

• Free Veritas GMAT Class
Experience Lesson 1 Live Free

Available with Beat the GMAT members only code

• Free Trial & Practice Exam
BEAT THE GMAT EXCLUSIVE

Available with Beat the GMAT members only code

• 5 Day FREE Trial
Study Smarter, Not Harder

Available with Beat the GMAT members only code

• Free Practice Test & Review
How would you score if you took the GMAT

Available with Beat the GMAT members only code

• 1 Hour Free
BEAT THE GMAT EXCLUSIVE

Available with Beat the GMAT members only code

• Reach higher with Artificial Intelligence. Guaranteed
Now free for 30 days

Available with Beat the GMAT members only code

• 5-Day Free Trial
5-day free, full-access trial TTP Quant

Available with Beat the GMAT members only code

## Math Question

This topic has 1 expert reply and 3 member replies
kashewman Newbie | Next Rank: 10 Posts
Joined
14 Aug 2006
Posted:
8 messages

#### Math Question

Sun Sep 10, 2006 10:58 am
I had one question that I don't seem to understand.

Algebra: [(1/5)^m] * [(1/4)^18] = 1/[2(10)^35]
what is m?

Any insight would be appreciated, thanks.

abby_g Junior | Next Rank: 30 Posts
Joined
30 Sep 2006
Posted:
24 messages
1
Sat Sep 30, 2006 2:06 am
The answer is : m = 35

RHS: 1/2(10)^35 = (1/5^35 )* (1/2^36)
= (1/5^35) * (1/4^18)

equate on both sides and woyla you get m = 35. Correct?

### GMAT/MBA Expert

Joined
13 Feb 2006
Posted:
6716 messages
Followed by:
966 members
1249
Sun Sep 10, 2006 7:34 pm
kashewman wrote:
Does anyone have a good formula for mixture problems? Thanks.
Check out page 48 of my GMAT Flashcards: http://www.beatthegmat.com/viewtopic.php?t=32

_________________
Beat The GMAT
Community Management Team

kashewman Newbie | Next Rank: 10 Posts
Joined
14 Aug 2006
Posted:
8 messages
Sun Sep 10, 2006 11:00 am
Does anyone have a good formula for mixture problems? Thanks.

aim-wsc Legendary Member
Joined
20 Apr 2006
Posted:
2470 messages
Followed by:
14 members
85
Target GMAT Score:
801-
Sun Sep 10, 2006 11:48 am
...err can you make some things clear?

like: 2(10)^35 did you mean [(2(10))^35]=20^35
or 2 X (10)^35

OK i presume its latter one.

Its a tricky one & i must confess i had to used my instincts

before i explain the answer, you must understand the following rule

given n>m
then
(a^m) X (b^n) = ((aXb)^m) X (b^(n-m))

eg. (5^4) X (3^6) = ((5X3)^4) X (3^2)
= (15 ^4) X 9

OK back to problem.
LHS:
(1/5)^m * (1/4)^18
this can be also wirtten as
(1/5)^m * (1/2)^36

RHS:
1/[2 X 10^35]= 1/[2 X (2X5)^35)]
=1/[(2^36) X (5^35)]

therefore
m=35

_________________
Getting started @BTG?

Please do not PM me, (not active anymore) contact Eric.

### Best Conversation Starters

1 lheiannie07 88 topics
2 Roland2rule 70 topics
3 ardz24 60 topics
4 LUANDATO 59 topics
5 M7MBA 50 topics
See More Top Beat The GMAT Members...

### Most Active Experts

1 Rich.C@EMPOWERgma...

EMPOWERgmat

138 posts
2 GMATGuruNY

The Princeton Review Teacher

131 posts
3 Brent@GMATPrepNow

GMAT Prep Now Teacher

129 posts
4 Jeff@TargetTestPrep

Target Test Prep

114 posts
5 Scott@TargetTestPrep

Target Test Prep

100 posts
See More Top Beat The GMAT Experts