Manhattan

This topic has expert replies
Master | Next Rank: 500 Posts
Posts: 118
Joined: Mon May 21, 2012 10:07 pm
Thanked: 23 times
Followed by:4 members

Manhattan

by das.ashmita » Tue Oct 16, 2012 2:22 am
If a and b are positive integers such that a < b, is b even?

(1) b/2 - a/2 is an integer.

(2) 3b/4 - a/2 is an integer.

OA B

Experts please tell me why A is not sufficient

Newbie | Next Rank: 10 Posts
Posts: 5
Joined: Wed Oct 03, 2012 2:30 am

by bj.1984 » Tue Oct 16, 2012 3:09 am
Answer. (2)

Answer (1) is insufficient because what if B and A are even numbers or what if B and A are odd numbers, in either you will get B/2 - A/2 as an integer.

User avatar
Master | Next Rank: 500 Posts
Posts: 279
Joined: Mon Jun 25, 2012 10:56 pm
Thanked: 60 times
Followed by:10 members

by anuprajan5 » Tue Oct 16, 2012 3:16 am
The answer is B

Statement 1 - It states (b-a)/2 is integer which means that b-a is even and b and a can be odd together or even together

(7-1) both odd
(6-2) both even

Insufficient

Statement 2 - It states that (3b-2a)/4 is an integer which means that 3b-2a is even.

a can be odd. But 2a is even and if 3b-2a needs to be an even integer, 3b needs to be even. Therefore b is even.

Sufficient.

Regards
Anup

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Tue Oct 16, 2012 6:48 am
das.ashmita wrote:If a and b are positive integers such that a < b, is b even?
(1) b/2 - a/2 is an integer.
(2) 3b/4 - a/2 is an integer.
Target question: Is b even?

Statement 1: b/2 - a/2 is an integer
We can combine the fractions to get (b-a)/2 is an integer.
If (b-a)/2 is an integer, then b-a must be even.
So, statement 1 is really just telling us that b-a is even. There are several pairs of values that satisfy this condition. Here are two:
case a: a=3 and b=5, in which case b is not even
case b: a=2 and b=6, in which case b is even
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: 3b/4 - a/2 is an integer
We can combine the fractions to get (3b-2a)/4 is an integer.
If (3b-2a)/4 is an integer, then 3b-2a must be divisible by 4.
If 3b-2a is divisible by 4, then 3b-2a must be even
Well, we know that 2a will be even for all integer values of a
So, if 3b - 2a is even then 3b must also be even.
If 3b is even, then b must be even
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer = B

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image