"A game is being played with a die. The die is rolled three times and each roll recorded. How many different arrangements are possible? What if previously rolled numbers do not count?" Manhattan Review/Chapter 10 Combinatorics Practice Problem #2
First of all, what is the question asking? Second, I do not believe Manhattan review has answer keys to practice questions. I have all 4 books, study guide and explanation guide.
Thanks in advance for posting an answer!
Manhattan Review/Combinatorics Question
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- harsh.champ
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Gat0rbabe wrote:"A game is being played with a die. The die is rolled three times and each roll recorded. How many different arrangements are possible? What if previously rolled numbers do not count?" Manhattan Review/Chapter 10 Combinatorics Practice Problem #2
First of all, what is the question asking? Second, I do not believe Manhattan review has answer keys to practice questions. I have all 4 books, study guide and explanation guide.
Thanks in advance for posting an answer!
What if previously rolled numbers do not count? - Thats quite confusing.
6^3.-That would be my answer.
i don't trust this question's source.
Help needed from tutors!!
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Just because something is hard doesn't mean you shouldn't try,it means you should just try harder.
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Sounds like it's two questions:
How many different combinations can you have?
and
How many different combinations can you have if you dont count rolls where a repeat number comes up (ie if you roll a 6 in the first roll, then u can't roll another 6. If you do, it doesn't count and u roll until u get something different than a 6).
The answer to the first would simply be 6^3 = 216
The answer to the second would be 6*5*4 = 120
How many different combinations can you have?
and
How many different combinations can you have if you dont count rolls where a repeat number comes up (ie if you roll a 6 in the first roll, then u can't roll another 6. If you do, it doesn't count and u roll until u get something different than a 6).
The answer to the first would simply be 6^3 = 216
The answer to the second would be 6*5*4 = 120