The integers m and p are such that 2 < m < p and m is not a factor of p. If r is the remainder when p is divided by m, is r > 1?
[1] The greatest common factor of m and p is 2.
[2] The least common multiple of m and p is 30.
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m is not a factor of p
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- sanju09
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Given that r > 0; to find whether r > 1.sanju09 wrote:The integers m and p are such that 2 < m < p and m is not a factor of p. If r is the remainder when p is divided by m, is r > 1?
[1] The greatest common factor of m and p is 2.
[2] The least common multiple of m and p is 30.
[spoiler]Source: www.avenuesabroad.org[/spoiler]
St1] This suggests that both m & p are even integers; this means r must be an even integer other than 0. Suff.
St2] Assume p = im + 1 and otherwise.
If p = im + 1, then m*p = 30. possible 5 & 6.
Otherwise 10 & 15. Insuff.
I pick A