Line

This topic has expert replies
Legendary Member
Posts: 869
Joined: Wed Aug 26, 2009 3:49 pm
Location: California
Thanked: 13 times
Followed by:3 members

Line

by heshamelaziry » Fri Nov 27, 2009 3:10 pm
How to get the slope of the line and the y intercept ?
Attachments
If the line passes through the origin.docx
(16.47 KiB) Downloaded 86 times

Senior | Next Rank: 100 Posts
Posts: 70
Joined: Mon May 12, 2008 12:26 pm
Thanked: 3 times

by adam15 » Fri Nov 27, 2009 10:16 pm
from the graph y=-7/4x
then
y=14*(-7/4)=-49/2

Legendary Member
Posts: 869
Joined: Wed Aug 26, 2009 3:49 pm
Location: California
Thanked: 13 times
Followed by:3 members

by heshamelaziry » Fri Nov 27, 2009 10:23 pm
i am not seeking a solution how do i get the slope without using k ? and how do i find out about the y intercept

Newbie | Next Rank: 10 Posts
Posts: 7
Joined: Mon Nov 16, 2009 1:01 pm
Thanked: 1 times

by salar_snake » Sat Nov 28, 2009 2:29 am
you can get the slope using this formula:

(y2 - y1) / (x2 - x1 )

here, it equals: (k - 7) / (14 - (-4)) = (k-7)/18

but u want to get the slope without using k, so use another pair of point: (0,0) and (-4,7)
which means the slope equals -7/4

and -7/4 = (k - 7)/18 ----> k = 98/ 4 = 24.5

also, since the line passes through point (0,0), the y intercept is (0,0).

now you can apply point (-4,7) to get k.

y = [(k-7)/18] x
7 = [(k-7)/18] (-4) ---> k = 98/ 4 = 24.5

Legendary Member
Posts: 869
Joined: Wed Aug 26, 2009 3:49 pm
Location: California
Thanked: 13 times
Followed by:3 members

by heshamelaziry » Sat Nov 28, 2009 10:44 am
Thank you salar_snake