The Points R, T, and U lie on a circle that has radius 4. If the length of arc RTU is (4* pi)/3, what is the length of the line segment RU?
A. 4/3
B. 8/3
C. 3
D. 4
E. 6
pi = 22/7 = 3.14
Lenth of Line Segment
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There is no gap in problem.stop@800 wrote:I think there is some gap with the problem.
Please verify all values.
I am getting ans as 20 * Pi / 3
here is the logic
r = 4
circumference = 8*pi
rtu is 4*pi/3
so remaining (=ru)
is
8*pi - 4*pi/3
= 20 * Pi / 3
From circumference and arc you get angle as 60 degree.
So this makes it equilateral triangle
Therefore length of segment is 4
IMO D
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imo D
let the centre of the circle be O.
length of the arc = 4*pi/3
radius of the circle = 4
circumference of the circle = 2*pi*r
= 2*pi*4
= 8*pi
Now,
Let angle ROU = x degrees
(4*pi/3)/(8*pi) = x/360
or x = 60 degrees
Therefore, ROU is an equilateral triangle.
Hence, length of side RU is 4 or Choice (D)
let the centre of the circle be O.
length of the arc = 4*pi/3
radius of the circle = 4
circumference of the circle = 2*pi*r
= 2*pi*4
= 8*pi
Now,
Let angle ROU = x degrees
(4*pi/3)/(8*pi) = x/360
or x = 60 degrees
Therefore, ROU is an equilateral triangle.
Hence, length of side RU is 4 or Choice (D)
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D it is ....bharathaitha wrote:The Points R, T, and U lie on a circle that has radius 4. If the length of arc RTU is (4* pi)/3, what is the length of the line segment RU?
A. 4/3
B. 8/3
C. 3
D. 4
E. 6
pi = 22/7 = 3.14
Length of the arc = 2*pi* r*theta/360
(4* pi)/3 = 2*pi* 4*theta/360
hence the angle is 60 degrees. = Equvilateral triangle .
hence the legth is 4.
hope its clear..