28 lawyers from 3 firms X, Y, Z. They can either belong to only 1 firm or belong to the three firms at the same time. X firm has 10 lawyers, Y has 11 lawyers and Z has 13 lawyers. How many people only belong to Z?
Solution: 10
10+11+13-2n=28 ----〉why 2n and not only n??
N=3
13-n=10
lawyers
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Becausegmattaker33 wrote: 10+11+13-2n=28 ----〉why 2n and not only n??
n=number of lawyers belonging to all three firms at the same time
10-n=lawyers only in X
11-n=lawyers only in Y
13-n=lawyers only in Z
Therefore the total number of lawyers is
(10-n)+(11-n)+(13-n)+n = 10+11+13-3n+n = 10+11+13-2n =28