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nisagl750
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We know the power cycle works fine to find out the last digit of any factorial (It will be zero for any factorial greater than 5) and any number raised to the power of another number.
For Eg: Last non zero digit of 123456^123456 = 6 (following the power cycle of 6 which always gives a 6)
I also know that last two non zero digits of a multiplication can be found out by multiplying last two digits of the numbers multiplied.
i.e. last two non zero units digit of 2345*162 = 45*62 = 2790, So last two non zero digits will be 79.
I wanted to know, Is there any formula to find out last two or last three non zero digits of a multiplication?
for eg: last two non zero digits of 237^169?
Is there any general formula or method that we can use to calculate last N non zero digits of a^b or a*b (where a & b can be any positive integers? )
For Eg: Last non zero digit of 123456^123456 = 6 (following the power cycle of 6 which always gives a 6)
I also know that last two non zero digits of a multiplication can be found out by multiplying last two digits of the numbers multiplied.
i.e. last two non zero units digit of 2345*162 = 45*62 = 2790, So last two non zero digits will be 79.
I wanted to know, Is there any formula to find out last two or last three non zero digits of a multiplication?
for eg: last two non zero digits of 237^169?
Is there any general formula or method that we can use to calculate last N non zero digits of a^b or a*b (where a & b can be any positive integers? )
