Japanese and French

IMO C

Suppose F students study French.. and J students study Japanese

Then, 4F/100 study both, Japanese and French

Stmt 1 - 16 students study French and Japanese

So, 4F/100 = 16 => F = 400 students study French. However, Q does not say anything else so NOT SUFF

Stmt 2 - 10J/100 study both French and Japanese... We cannot determine anything about French Students so NOT SUFF

Together, 10J/100 = 4F/100 = 16

Solve to get J = 160 which is less than 400 SUFF

OA??

OA is B

For (2):

If # Students taking Japanese = 100 then the number of students taking Japanese and French = 10. # Students taking French = 4/100x = 10 = 250

250 > 100

If # Students taking Japanese = 200 then the number of students taking Japanese and French = 20. # Students taking French = 4/100x = 20 = 500

500 > 200

Answer is B.

***Alternatively***

(10/100)*J = (4/100)*F
10J = 4F
J/F = 2/5

luvaduva wrote:For (2):

If # Students taking Japanese = 100 then the number of students taking Japanese and French = 10. # Students taking French = 4/100x = 10 = 250

250 > 100

If # Students taking Japanese = 200 then the number of students taking Japanese and French = 20. # Students taking French = 4/100x = 20 = 500

500 > 200

Answer is B.

***Alternatively***

(10/100)*J = (4/100)*F
10J = 4F
J/F = 2/5

Small corrections to the above: 4/100x should be read as (4/100) *x
or 4x/100

rgds
-Vittal