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Jane reads Faster

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Jane reads Faster

by kanha81 » Fri Sep 11, 2009 4:36 pm
Please HELP

Tom reads at an average rate of 30 pages per hour, while Jan reads at an average rate of 40 pages per hour. If Tom starts reading a novel at 4:30, and Jan begins reading an identical copy of the same book at 5:20, at what time will they be reading the same page?

(A) 9:30
(B) 9:00
(C) 8:40
(D) 7:50
(E) 7:00
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by bharathh » Fri Sep 11, 2009 4:50 pm
Tom reads 30 pages per hour... = 0.5 pages per minute = 5 pages in 10 mins.

So given that he has a 50 min head start.

He will read 50*0.5 = 25 pages before Jan starts

So at 5:20 T = 25, J = 0
6:20 T = 55, J = 40
7:20 T = 85, J = 80
8:20 T = 115, J = 120

Ok so Jan overtook Tom... so the value has to be between 7:20 and 8:20. There is only one value that is so .. So D
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by PAB2706 » Sun Sep 13, 2009 5:57 am
Kanha,

u can solve this is not more than 30 secs...

heres how...

when jane starts reading, tom is already 50mins ahead of jane.

thus in those 50 mins tom has read 30*5/6=25 pages.

The relative speed of tom and jane is 10pages per hour...

so jane will catch up with tom in 25/10=2.5 hours.

So D
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