Data Sufficiency

[Math Revolution GMAT math practice question]

Is x>x/y?

1) y>1
2) xy>0

Max@Math Revolution wrote:[Math Revolution GMAT math practice question]

Is x>x/y?

1) y>1
2) xy>0

\[x\,\,\mathop > \limits^? \,\,\frac{x}{y}\]
\[\left( 1 \right)\,\,\,y > 1\,\,\,\left\{ \begin{gathered}
\,{\text{Take}}\,\,\left( {0,2} \right)\,\,\,\, \Rightarrow \,\,\,\left\langle {{\text{NO}}} \right\rangle \,\, \hfill \\
\,{\text{Take}}\,\,\left( {1,2} \right)\,\,\,\, \Rightarrow \,\,\,\left\langle {{\text{YES}}} \right\rangle \,\, \hfill \\
\end{gathered} \right.\]
\[\left( 2 \right)\,\,\,xy > 0\,\,\,\left\{ \begin{gathered}
\,{\text{Take}}\,\,\left( {1,2} \right)\,\,\,\, \Rightarrow \,\,\,\left\langle {{\text{YES}}} \right\rangle \hfill \\
\,{\text{Take}}\,\,\left( {1,1} \right)\,\,\,\, \Rightarrow \,\,\,\left\langle {{\text{NO}}} \right\rangle \,\,\,\, \hfill \\
\end{gathered} \right.\]
\[\left( {1 + 2} \right)\,\,\,\, \Rightarrow \,\,\,\,x,y\,\, > 0\,\,\,\]
\[x\,\,\mathop > \limits^? \,\,\frac{x}{y}\,\,\,\,\,\mathop \Leftrightarrow \limits^{:\,\,x\,\, > \,\,0} \,\,\,\,1\,\,\mathop > \limits^? \,\,\,\frac{1}{y}\,\,\,\,\,\mathop \Leftrightarrow \limits^{ \cdot \,\,y\,\, > \,\,0} \,\,\,\,y\,\,\mathop > \limits^? \,\,\,1\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\left\langle {{\text{YES}}} \right\rangle \]

The correct answer is therefore [spoiler]__(C)______[/spoiler] .

This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question.

The question x>x/y is equivalent to xy(y-1) > 0 as shown below:
x>x/y
=> xy^2 > xy since y^2 > 0
=> xy^2 - xy > 0
=> xy(y - 1) > 0

Condition 1) tells us that y - 1 > 0, and condition 2) tells us that xy > 0. Thus, both conditions together are sufficient.

Therefore, C is the answer.