Gmat_mission wrote:Is x² > 15?
(1) x > -4
(2) x³ < 0
[spoiler]OA=E[/spoiler]
Source: Veritas Prep
Target question: Is x² > 15?
Statement 1: x > -4
Let's TEST some values.
There are several values of x that satisfy statement 1. Here are two:
Case a: x = -1. In this case, x² = (-1)² = 1. So, the answer to the target question is
NO, x² is NOT greater than 15
Case b: x = -3.99999. In this case, x² = (-3.99999)² ≈ 16. So, the answer to the target question is
YES, x² IS greater than 15
Since we cannot answer the
target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: x³ < 0
In other words, statement 2 is telling us that
x is negative
Let's TEST some values.
ASIDE: When testing values for statement 2, see if you can re-use any of the cases you tested for statement 1.
Here it turns out we can re-use BOTH cases:
Case a: x = -1. In this case, x² = (-1)² = 1. So, the answer to the target question is
NO, x² is NOT greater than 15
Case b: x = -3.99999. In this case, x² = (-3.99999)² ≈ 16. So, the answer to the target question is
YES, x² IS greater than 15
Since we cannot answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined
IMPORTANT: Notice that I was able to use the
same counter-examples to show that each statement ALONE is not sufficient. So, the same counter-examples will satisfy the two statements COMBINED.
In other words,
Case a: x = -1. In this case, x² = (-1)² = 1. So, the answer to the target question is
NO, x² is NOT greater than 15
Case b: x = -3.99999. In this case, x² = (-3.99999)² ≈ 16. So, the answer to the target question is
YES, x² IS greater than 15
Since we cannot answer the
target question with certainty, the combined statements are NOT SUFFICIENT
Answer: E
Cheers,
Brent
