Is SQRT[(x-3)^2] = 3-x
[/u]1st step
I rephrased as: is |x-3|=x-3
Solution a: x-3=3-x => x=3
Solution b: x-3 = -(3-x)... 0=0...not valid
So, only solution a is valid i.e is x=3?
Implying A is sufficient
2nd step
However, testing #s shows that all values less than 2 are valid.
In this case, B is sufficient.
Someone pls help identify my error in the 1st step as OA is not A.
Thanks.
[/u]1st step
I rephrased as: is |x-3|=x-3
Solution a: x-3=3-x => x=3
Solution b: x-3 = -(3-x)... 0=0...not valid
So, only solution a is valid i.e is x=3?
Implying A is sufficient
2nd step
However, testing #s shows that all values less than 2 are valid.
In this case, B is sufficient.
Someone pls help identify my error in the 1st step as OA is not A.
Thanks.














