Is k the square of an integer? $$(1)\ \ \ k=t^2*q^6*r^{10}\ ,\ where\ t,\ q\ and\ r\ are\ integers.$$ $$(2)\ \ k=t^2*m^{15}\ ,\ where\ \ t\ and\ m\ are\ integers.$$ [spoiler]OA=A[/spoiler].
Why is A the correct answer? Can someone give me an explanation? Please.
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Is k the square of an integer?
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Hello.
I'd solve it like this: $$\left(1\right)\ \ \ k=t^2\cdot q^6\cdot r^{10}$$ If we rewrite this expression we get: $$k=t^2\cdot\left(q^3\right)^2\cdot\left(r^5\right)^2\ =\ \ \left(t\cdot q^3\cdot r^5\right)^2.$$ Since t, q and r are integers, then t*q^3 * r^5 is an integer. Therefore, this statement is SUFFICIENT. $$\left(2\right)\ \ \ k=t^2\cdot m^{15}$$ If we rewrite this expression we will get $$k=t^2\cdot\left(m^{\frac{15}{2}}\right)^2=\left(t\cdot m^{\frac{15}{2}}\right)^2\ .$$ Now, since we don't know the value of m, we can't sy that m^(15/2) is integer. Therefore, this statement is NOT SUFFICIENT.
This is why the correct answer is the option A.
I'd solve it like this: $$\left(1\right)\ \ \ k=t^2\cdot q^6\cdot r^{10}$$ If we rewrite this expression we get: $$k=t^2\cdot\left(q^3\right)^2\cdot\left(r^5\right)^2\ =\ \ \left(t\cdot q^3\cdot r^5\right)^2.$$ Since t, q and r are integers, then t*q^3 * r^5 is an integer. Therefore, this statement is SUFFICIENT. $$\left(2\right)\ \ \ k=t^2\cdot m^{15}$$ If we rewrite this expression we will get $$k=t^2\cdot\left(m^{\frac{15}{2}}\right)^2=\left(t\cdot m^{\frac{15}{2}}\right)^2\ .$$ Now, since we don't know the value of m, we can't sy that m^(15/2) is integer. Therefore, this statement is NOT SUFFICIENT.
This is why the correct answer is the option A.
