is it possible to write x as a terminating decimal?

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Hello,

Can you please assist with this? This question is from MGMAT. Thanks for your help.

If 0 < x < 1, is it possible to write x as a terminating decimal?

(1) 24x is an integer.

(2) 28x is an integer.


OA: C

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by ani781 » Sat Sep 14, 2013 8:37 pm
Hi gmattesttaker2,
Terminating decimal means that there are finite number of digits following the decimal.
e.g. 1/2=0.5 is a terminating decimal, whereas 1/3 = 0.33333... is not a terminating decimal. Now 1 divided by 3 or 7 or their multiples would always result in a non terminating decimal. Whereas 1 divided by 2 or 5 or their multiples would result in a terminating decimal.

We know 0<x<1
Now let us look at the options.
(1) 24x is an integer. 24's factors are 2,3,4,6,12 & 24. Therefore 24x would be an integer only if x = 1/2, 1/3, 1/4, 1/6 , 1/12 or 1/24. Out of these 1/2 is terminating ( 0.5) , so is 1/4 (0.25) or 1/8(0.125).... whereas 1/3 (0.3333...) or 1/12 or 1/24 are not. So Insufficient.

(2) 28x is an integer. Following the same reason as above, this results in x = 1/2 or 1/4 or 1/7 or 1/14 or 1/28. Clearly, in this case also , 1/2 and 1/4 are terminating , whereas 1/7 or 1/14 or 1/28 are not. Insufficient.

Combining, we can say that 1/2 and 1/4 are the only two values of x , which enable writing x as a terminating decimal. Hence Sufficient. So OA is C

Hope this makes it clear.

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by Java_85 » Sun Sep 15, 2013 4:32 pm
IMO also it's C, same explanation as ani's,

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by Java_85 » Sun Sep 15, 2013 4:32 pm
IMO C, Same explanations as ani's.

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by theCodeToGMAT » Mon Sep 16, 2013 12:36 am
gmattesttaker2 wrote:Hello,

Can you please assist with this? This question is from MGMAT. Thanks for your help.

If 0 < x < 1, is it possible to write x as a terminating decimal?

(1) 24x is an integer.

(2) 28x is an integer.


OA: C

Numbers That can produce non-terminating decimals : 3 & 7.
X can be number which can contain 3 or 7 or both. So, inorder to be sure that X is terminating we need both "3"and "7
(1) 24x = 3 x 2 x 2 x 2 --> "7" is missing.. Insufficent
(2) 28x = 7 x 2 x 2 --> "3" is missing.. Insufficient
Combining (1) & (2) ..... both 3 and 7 are present... So,.. [C]

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by Brent@GMATPrepNow » Mon Sep 16, 2013 6:28 am
gmattesttaker2 wrote: If 0 < x < 1, is it possible to write x as a terminating decimal?

(1) 24x is an integer.
(2) 28x is an integer.

Target question: Is it possible to write x as a terminating decimal?

This is a great candidate for rephrasing the target question. Aside: We have a free video with tips on rephrasing the target question: https://www.gmatprepnow.com/module/gmat- ... cy?id=1100

Given: 0 < x < 1
Let's say that x = a/b where the fraction a/b is written in simplest terms.
There's a nice rule that says something like,
If a/b results in a terminating decimal, then the denominator, b, MUST be the product of 2's and 5's only!
So, for example, if b = 20, the fraction a/b will result in a terminating decimal. The same holds true for other values of b such as 4, 5, 25, 40, 2, 8, and so on.

REPHRASED target question: Is b the product of 2's and 5's only?

Statement 1: 24x is an integer.
x = a/b. So, if 24x is an integer, b must be a divisor of 24.
So, b could equal 2, 3, 4, 6, 8, 12, or 24 [aside: I omitted 1 as a possibility, since we're told that 0 < x < 1]
So, for example, b could equal 8, in which case b IS the product of 2's and 5's only
Or b could equal 3, in which case b is NOT the product of 2's and 5's only
Since we cannot answer the REPHRASED target question with certainty, statement 1 is NOT SUFFICIENT


Statement 2: 28x is an integer.
x = a/b. So, if 28x is an integer, b must be a divisor of 28.
So, b could equal 2, 4, 7, 14, or 28
So, for example, b could equal 4, in which case b IS the product of 2's and 5's only
Or b could equal 7, in which case b is NOT the product of 2's and 5's only
Since we cannot answer the REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Statement 1 says that b could equal 2, 3, 4, 6, 8, 12, or 24
Statement 2 says that b could equal 2, 4, 7, 14, or 28
So, we can conclude that b = 2 or 4
Both of these possible b values ARE the product of 2's and 5's only.
Since we can answer the target question with certainty, the combined statements are SUFFICIENT

Answer = C

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Brent
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by mikepamlyla » Wed Jun 25, 2014 11:50 am
Brent,

Great explanation. But isn't 8 a factor of only 2s and 5s (2x2x2)?

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by Brent@GMATPrepNow » Wed Jun 25, 2014 12:11 pm
mikepamlyla wrote:Brent,

Great explanation. But isn't 8 a factor of only 2s and 5s (2x2x2)?
Yes it is, and EVERY fraction with 8 in the denominator (e.g., 1/8, 2/8, 3/8, etc.) can be written as a terminating decimal.
1/8 = 0.125
2/8 = 0.25
3/8 = 0.375
etc

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by GMATinsight » Sat Jun 28, 2014 12:41 am
If 0 < x < 1, is it possible to write x as a terminating decimal?

(1) 24x is an integer.

(2) 28x is an integer.
To Solve the question we should know about an observation about the fractions which is any fraction, in it's lowest possible form, will be NON-terminating if the denominator has any prime factor other than 2 and 5

Statement 1) It only mentions that denominator of x is a a factor of 24 because 24x is an integer.

Therefore x can be reciprocal of 2,3,4,6,12,24 but if x is 1/2 then it's terminating and if x is 1/3 then it's non-terminating therefore INSUFFICIENT

Statement 2) It only mentions that denominator of x is a a factor of 28 because 28x is an integer.

Therefore x can be reciprocal of 2,4,7,14,24 but if x is 1/2 then it's terminating and if x is 1/7 then it's non-terminating therefore INSUFFICIENT

COMBINING the two statement
Denominator of x has to be factor of 24 and 28 both so possible values of x are reciprocal of 2 or 4 and in both cases x is a TERMINATING decimal therefore SUFFICIENT


Hence Answer option C
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