Is 3^(a^2/b) < 1?
(1) a<0
(2) b<0
The OA is C .
Experts, what is the best way to solve this DS question? Can you help me?
Is 3^(a^2/b) < 1?
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For 3^(a^2/b) to be less than 1, note that a^2/b must be less than 0. Since a^2 is always a non-negative number, it can be 0 or a positive number. But a must not be 0 since at a = 0, the power a^2/b would be 0 and 3^0 would be 1 (Not less than 1).M7MBA wrote:Is 3^(a^2/b) < 1?
(1) a<0
(2) b<0
The OA is C .
Experts, what is the best way to solve this DS question? Can you help me?
So, we need to see two conditions: 1. a ≠0 and 2. b must be negative.
(1) a<0
Insufficient. We do not know whether b is negative.
(2) b<0
Insufficient. We do not know whether a is not 0.
(1) and (2) together
Sufficient.
The correct answer: C
Hope this helps!
-Jay
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