BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Integers

Expert replies
by irock » Fri Jun 03, 2011 1:06 am

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty—

Is the range of the integers 6, 3, y, 4, 5, and x greater
than 9 ?

(1) y > 3x
(2) y > x > 3

OA C
We are what we repeatedly do. Excellence, therefore, is not an act but a habit - Aristotle.
Join the discussion
Source: — Data Sufficiency |

by cans » Fri Jun 03, 2011 1:13 am
integers are 3,4,5,6,x,y
range = largest-smallest
a)y>3x. if x=1, y>3 let it be 4. Range = 6-1 = 5<9
if x=1, y>3 let it be 100 range = 100-1 = 99>9
insufficient
b)y>x>3
x=4,y=5 => range = 6-3 = 3 <9
x=10,y=13 =>range = 13-3=10> 9
Insufficient
a&b together) y>3x and x>3
it means x is atleast 4 and thus y>12 or y is atleast 13
range=y-3 = as min y is 13, y-3 is minimum 10 thus range >9
Sufficient
IMO C
If my post helped you- let me know by pushing the thanks button ;)

Contact me about long distance tutoring!
[email protected]

Cans!!
Join the discussion

answer

by [email protected] » Mon Feb 19, 2018 2:25 pm
Hi All,

We're given a set of 6 INTEGERS: 3, 4, 5, 6, X and Y. We're asked if the range is GREATER than 9. This is a YES/NO question. We can solve it by TESTing VALUES.

1) Y > 3X

IF.....
X=1 and Y=4, then the range = 6-1 = 5 and the answer to the question is NO
X=4 and Y=13, then the range = 13 - 3 - 10 and the answer to the question is YES
Fact 1 is INSUFFICIENT

2) Y > X > 3
X=4 and Y=5, then the range = 6-3 = 3 and the answer to the question is NO
X=4 and Y=13, then the range = 13 - 3 - 10 and the answer to the question is YES
Fact 2 is INSUFFICIENT

Combined, we know:
Y > 3X
Y > X > 3

Since both X and Y are INTEGERS and X>3, we know that X is AT LEAST 4... and since Y > 3X, this means that Y is AT LEAST 13. As X gets bigger, Y would also get bigger. Since the lowest value in the group is 3, the range of the group will ALWAYS be AT LEAST 13-3 = 10. Thus, the answer to the question is ALWAYS YES.

Final Answer: C

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by ceilidh.erickson » Fri Feb 23, 2018 11:22 am
irock wrote:Is the range of the integers 6, 3, y, 4, 5, and x greater than 9 ?

(1) y > 3x
(2) y > x > 3

OA C
Before looking at the statements, REPHRASE the question stem.

First, put the known values in order: 3, 4, 5, 6. The range of the values that we know is 6 - 3 = 3. We would know that we had a range greater than 9 if one of our variables was less than -3 (6 - -3 = 9) or greater than 12 (12 - 3 = 9).

Target question: is either x or y less than -3 or greater than 12?

(1) y > 3x
Test small values:
x = 0
y = 1
Answer to target question: no.

Test a large value:
x = 0
y = 100
Answer to target question: yes.
Insufficient.

(n.b. when testing cases with 2 variables, it's often helpful to keep 1 variable constant, and only change the other one).

(2) y > x > 3
Test small values:
x = 4
y = 5
Answer to target question: no.

Test a large value:
x = 4
y = 100
Answer to target question: yes.
Insufficient.

(1) & (2) together: y > 3x and y > x > 3
Test small values:
x = 4 (smallest possible value of x)
y = 13 (smallest possible integer greater than 3x)
Answer to target question: yes.

Test a large value... we don't have to. The larger x gets, the larger y gets, and we'll definitely have a value greater than 12. Sufficient.

The answer is C.
Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education
Join the discussion

by Jeff@TargetTestPrep » Tue May 29, 2018 5:18 pm
irock wrote:Is the range of the integers 6, 3, y, 4, 5, and x greater
than 9 ?

(1) y > 3x
(2) y > x > 3
Statement One Alone:

y > 3x

Statement one is not sufficient to answer the question. For example, if x = 0, y could be 1 and the range is 6 - 0 = 6, which is less than 9. However, if x = 10, y could be 31 and the range is 31 - 3 = 28, which is greater than 9.

Statement Two Alone:

y > x > 3

Statement two is not sufficient to answer the question. For example, if x = 4, y could be 5 and the range is 6 - 0 = 6, which is less than 9. However, if x = 14, y could be 15 and the range is 15 - 3 = 12, which is greater than 9.

Statements One and Two Together:

From the two statements, we know that x > 3 and y > 3x. So the smallest integer x can be is 4 and the smallest integer y can be is 3(4) + 1 = 13. Thus the smallest range of the integers is 13 - 3 = 10, which is greater 9. Since 10 is the smallest range, any other range of the integers will be greater than 10 and hence greater than 9.

Answer: C

Jeffrey Miller
Head of GMAT Instruction
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews
Join the discussion