Integers - experts please help

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Integers - experts please help

by VyDinh » Sat Sep 14, 2013 5:45 am
I take GMAT Prep test and get stuck with this question. Please help!

If p and n are positive integers and p>n, what is the remainder when p2 -n2 is divisible by 5?

1) The remainder when p+n is divisible by 5 is 1
2) The remainder when p-n is divisible by 3 is 1

Thank you for your help!!

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by vinay1983 » Sat Sep 14, 2013 6:55 am
Is the answer E?
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by Brent@GMATPrepNow » Sat Sep 14, 2013 7:01 am
VyDinh wrote:If p and n are positive integers and p>n, what is the remainder when p² - n² is divided by 15?

1) The remainder when p+n is divided by 5 is 1
2) The remainder when p-n is divided by 3 is 1
NOTE: You have transcribed the original GMATPrep question incorrectly in a few places. The corrections are made in red.

Target question: What is the remainder when p² - n² is divided by 15

Rephrased target question: What is the remainder when (p + n)(p - n) is divided by 15?

For this question, we're going to use a nice rule that says:
If N divided by D, leaves remainder R, then the possible values of N are R, R+D, R+2D, R+3D,. . . etc.
For example, if k divided by 5 leaves a remainder of 1, then the possible values of k are: 1, 1+5, 1+(2)(5), 1+(3)(5), 1+(4)(5), . . . etc.

Okay, onto the question . . .

Statement 1: The remainder when p+n is divided by 5 is 1
Since there's no information about p-n, statement 1 is NOT SUFFICIENT.

Statement 2: The remainder when p-n is divided by 3 is 1
Since there's no information about p+n, statement 2 is NOT SUFFICIENT.

Statements 1 and 2 combined
Statement 1: Applying the above rule, some possible values of p+n are 6, 11, 16, 21, 26, etc.
Aside: you'll notice that I didn't include 1 as a possible value since we're told that p and n are positive integers, and we can't get a sum of 1 if both are positive

Statement 2: Applying the above rule, some possible values of p-n are 1, 4, 7, 10, 13, etc

Let's examine two cases with conflicting results.

case a: p+n = 11 and p-n = 1
Add the equations to get 2p = 12, which means p = 6 and n = 5 (perfect, we have positive integer values for p and n)
In this case, when (p + n)(p - n) is divided by 15, the remainder is 11

case b: p+n = 6 and p-n = 4
Add the equations to get 2p = 10, which means p = 5 and n = 1 (perfect, we have positive integer values for p and n)
In this case, when (p + n)(p - n) is divided by 15, the remainder is 9
Since we cannot answer the target question with certainty, the combined statements are NOT SUFFICIENT

Answer = E

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by VyDinh » Sat Sep 14, 2013 7:55 am
Thanks for your correction and explanation!

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by vinay1983 » Sat Sep 14, 2013 10:45 am
I think the option is E. given condition is p > n and we are asked (p^2-n^2)/5 = ? some value(one specific value)


Statement 1

the numbers satisfying this condition are 6,11,16,21,26,31
let's take 6 can be written as 5+1 only(condition p > n) then 5^2-1^2= 25-1=24/5=4 remainder

Let's take 11, which can be written as 6+5, then 6^2-5^2=36-25=11/5=1

not sufficient

Statement 2

the numbers can be 4,7,10,13,16,19,22,25,28,31

Let's take 4, i.e 6-2 or 5-1,

for 6-2 it is 6^2-2^2=36-4=32/5=2

for 5-1 it is 5^2-1^2=25-1=24/5=4, hence not sufficient

Combining both statements number 31 when divided by both 5 and 3 gices remainder 1

but 31 can be written as 26+5, 27+4, 20+11, 16+15

So let's take 26+5= 26^2-5^2= 676-25=651/5=1

Let's take 27+4= 27^2-4^2=729-16=713/5=3

no one value obtained hence insufficient
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by vinay1983 » Sat Sep 14, 2013 11:16 am
I think the option is E. given condition is p > n and we are asked (p^2-n^2)/5 = ? some value(one specific value)


Statement 1

the numbers satisfying this condition are 6,11,16,21,26,31
let's take 6 can be written as 5+1 only(condition p > n) then 5^2-1^2= 25-1=24/5=4 remainder

Let's take 11, which can be written as 6+5, then 6^2-5^2=36-25=11/5=1

not sufficient

Statement 2

the numbers can be 4,7,10,13,16,19,22,25,28,31

Let's take 4, i.e 6-2 or 5-1,

for 6-2 it is 6^2-2^2=36-4=32/5=2

for 5-1 it is 5^2-1^2=25-1=24/5=4, hence not sufficient

Combining both statements number 31 when divided by both 5 and 3 gices remainder 1

but 31 can be written as 26+5, 27+4, 20+11, 16+15

So let's take 26+5= 26^2-5^2= 676-25=651/5=1

Let's take 27+4= 27^2-4^2=729-16=713/5=3

no one value obtained hence insufficient
You can, for example never foretell what any one man will do, but you can say with precision what an average number will be up to!