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## Integers equally spaced on a line - help?

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### Integers equally spaced on a line - help?

by saritalr » Mon Aug 09, 2010 10:17 am
This problem threw me off the first time around. Now I understand how to set up the equation but I'm having trouble with the algebra. First the problem:

[Image of 4 integers A, B, C, and D on a number line]
The integers A, B, C, and D shown on the number line above are all equally spaced. If C and D are equal to 5^12 and 5^13, respectively, what is the value of A?
• 1. 5^11
2. 5^10
3. -5^12
4. (-7)5^12
5. (-12)5^13

I can set up the equation: [spoiler]D minus three times the difference between C and D (or) 5^13 - 3(5^13-5^12) = A.[/spoiler] But after that, I'm lost with the algebra.

Below is the algebra for the right answer:
[spoiler]5^13 - 3(5^13 - 5^12)
5^13 - 3[5^12(5 - 1)]
5^13 - 3(5^12)(4)
5(5^12)- 12(5^12)
(-7)5^12

Can someone explain what operations are taking place in the first 2 lines?

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by selango » Mon Aug 09, 2010 10:29 am
The integers are equally spaced.

A+x=B

B+x=C

C+x=D

x is an difference between 2 integers.

Now C=5^12 and D=5^13

5^12+X=5^13

x=5^13-5^12=5^12(5-1)=4.5^12

Since the integers are equally spaced.

A+3x=D

A+3(4.5^12)=5^13

A+12.5^12=5^13

A=5^13-12.5^12=5^12(5-12)

=-7.5^12

Hope this clarify.
--Anand--

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by nicolezl » Mon Aug 09, 2010 10:44 am
saritalr wrote:5^13 - 3(5^13 - 5^12)
5^13 - 3[5^12(5 - 1)]
5^13 - 3(5^12)(4)
5(5^12)- 12(5^12)
(-7)5^12

Can someone explain what operations are taking place in the first 2 lines?

In the second line, you factor out 5^12 from (5^13 - 5^12), which gives you 5^12*(5-1).

Does that help?

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by selango » Mon Aug 09, 2010 10:45 am
saritalr,

Your approach is also same and correct..

[spoiler]5^13 - 3(5^13-5^12) = A

=5^13-3.5^12(5-1)

=5^13-12.5^12

=5^12(5-12)=-7.5^12[/spoiler]
--Anand--

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by saritalr » Mon Aug 09, 2010 10:55 am
selango wrote:
A=5^13-12.5^12=5^12(5-12)

=-7.5^12
Thanks Selango. Can you explain the above line - are you factoring something out?

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by saritalr » Mon Aug 09, 2010 10:56 am
nicolezl wrote:
In the second line, you factor out 5^12 from (5^13 - 5^12), which gives you 5^12*(5-1).

Does that help?
Very helpful! Just what I needed - thank you!

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by selango » Mon Aug 09, 2010 4:33 pm
saritalr wrote:
selango wrote:
A=5^13-12.5^12=5^12(5-12)

=-7.5^12
Thanks Selango. Can you explain the above line - are you factoring something out?
A=5^13-12.5^12

Here I am taking 5^12 as common factor.

=5^12(5-12)

=5^12(-7)

Hope this clarify.
--Anand--

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