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Initially, the markers and pens in a drawer were in the ratio 5:7. Then, 6 pens were removed. If there are 35 markers in

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by AAPL » Fri Jul 01, 2022 9:44 am
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Initially, the markers and pens in a drawer were in the ratio 5:7. Then, 6 pens were removed. If there are 35 markers in the drawer, how many pens are left?

A. 29
B. 43
C. 49
D. 50
E. 51

OA B
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Re: Initially, the markers and pens in a drawer were in the ratio 5:7. Then, 6 pens were removed. If there are 35 marker

by Scott@TargetTestPrep » Wed Jan 25, 2023 10:55 am
AAPL wrote: ↑
Fri Jul 01, 2022 9:44 am
 Manhattan Prep

Initially, the markers and pens in a drawer were in the ratio 5:7. Then, 6 pens were removed. If there are 35 markers in the drawer, how many pens are left?

A. 29
B. 43
C. 49
D. 50
E. 51

OA B
Since the ratio of markers to pens was 5 : 7, the number of markers can be represented by 5x and the number of pens can be represented by 7x where x is some positive integer. We can create the equation for the number of markers:

5x = 35

x = 7

Originally, there were 35 markers and 7 x 7 = 49 pens. Since 6 pens were removed, 43 pens were left in the drawer.

Answer: B

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