Given that S>0. Is S>T?
(1) | st | = t
(2) | st | = 7
inequalities with mod ds
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IMO E
1)| st | = t
t>o
s=1
says nothing else. t may or may not be <s
2)| st | = 7
if st is positive
t=7/s, again s may or may not be >t
ex: t=50, s=7/50
t=1/2,s=14
when st is negative
-st=7
t<0
not sufficient
combined
t>0
s=1
t may be>1
may be<1
not sufficient
1)| st | = t
t>o
s=1
says nothing else. t may or may not be <s
2)| st | = 7
if st is positive
t=7/s, again s may or may not be >t
ex: t=50, s=7/50
t=1/2,s=14
when st is negative
-st=7
t<0
not sufficient
combined
t>0
s=1
t may be>1
may be<1
not sufficient
The powers of two are bloody impolite!!
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would go with C
stment 1 and 2 are not sufficient,
together, s=1, t>0 from stmnt 1
from stmnt 2 : | st | = 7
=> |t|=7 , t>0
=>t=7
=> s(1) is always less than t(7)
stment 1 and 2 are not sufficient,
together, s=1, t>0 from stmnt 1
from stmnt 2 : | st | = 7
=> |t|=7 , t>0
=>t=7
=> s(1) is always less than t(7)
ern5231 wrote:Given that S>0. Is S>T?
(1) | st | = t
(2) | st | = 7
from 1
t is 0 and s anything or s = 1 (s is +ve given ) and t is +ve or -ve
from 2
s,t could be anything
both
t = 7 or -7thus s = 1...insuff
E
Last edited by yezz on Mon Aug 17, 2009 11:09 am, edited 1 time in total.
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It's C
When both statements are combined, T MUST BE POSITIVE. The left side of the equation is an absolute value, which is positive. Therefore, T unmodified must be positive.
With |ST| = T, we know that S is 1 b/c the passage already states that S > 0. Therefore, S cannot be -1.
We know that T unmodified is +7 because the absolute value on the left side is positive.
We now know that T = 7 and S = 1, so S is not greater than T.
When both statements are combined, T MUST BE POSITIVE. The left side of the equation is an absolute value, which is positive. Therefore, T unmodified must be positive.
With |ST| = T, we know that S is 1 b/c the passage already states that S > 0. Therefore, S cannot be -1.
We know that T unmodified is +7 because the absolute value on the left side is positive.
We now know that T = 7 and S = 1, so S is not greater than T.
- adilka
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The answer cannot be A simply because here are 2 conflicting solutions that would satisfy (1)ern5231 wrote:Even I feel it should be C but it's surprising that the Answer given is A! Can any of the instructors help us out?
Either you missed something in conditions / problem formulation or the OA is wrong.
1) S=1, T=7 hence S<T
2) S=1, T=0.5, hence S>T
both satisfy |ST|=T
Last edited by adilka on Wed Aug 19, 2009 7:23 am, edited 1 time in total.
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imo OA is correct
as with statement 1 we can find only one possible value as S=1 and T=0 in order to consider it true which implies==> s>t and hence suff
Statement 2
value of s can be 7/2,7/3,7/4
and corresponding value of t can be 2,3,4
and condition S>t is not proved and hence not suff
as with statement 1 we can find only one possible value as S=1 and T=0 in order to consider it true which implies==> s>t and hence suff
Statement 2
value of s can be 7/2,7/3,7/4
and corresponding value of t can be 2,3,4
and condition S>t is not proved and hence not suff
It does not matter how many times you get knocked down , but how many times you get up
yes, i agree that A is the answer.
For example,
if s=1 t=7, s is not greater than t
if s=1 t=1, s is not greater than t
I cannot find any value of s and t that satisfies the condition 1, and gives s > t.
And, second condition is not sufficient as :
if s=1 t=7, then s is not greater than t
if s=1 t=-7, then s is greater than t
For example,
if s=1 t=7, s is not greater than t
if s=1 t=1, s is not greater than t
I cannot find any value of s and t that satisfies the condition 1, and gives s > t.
And, second condition is not sufficient as :
if s=1 t=7, then s is not greater than t
if s=1 t=-7, then s is greater than t
- adilka
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ANDxcusemeplz2009 wrote:imo OA is correct
as with statement 1 we can find only one possible value as S=1 and T=0 in order to consider it true which implies==> s>t and hence suff
s=1, t=7 ??acenikk wrote:I cannot find any value of s and t that satisfies the condition 1, and gives s > t
s=1, t=0.565 ??
Last edited by adilka on Wed Aug 19, 2009 7:22 am, edited 1 time in total.
ok seriously...some of the explainations here are truly puzzling!!
Stmt 1 says:
|st|=t
If: s=1 (Since s>0) and t = 1, it satisfies. And this means: S=T and therefore: S not greater than t
Hence: 1 alone not sufficient
Stmt 2 says:
|st|=7
Here: S>0 so t can be +ve or -ve. Hence not enough
Combining:
t=7
So answer is C
right???
Stmt 1 says:
|st|=t
If: s=1 (Since s>0) and t = 1, it satisfies. And this means: S=T and therefore: S not greater than t
Hence: 1 alone not sufficient
Stmt 2 says:
|st|=7
Here: S>0 so t can be +ve or -ve. Hence not enough
Combining:
t=7
So answer is C
right???
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Given that S>0. Is S>T?
(1) | st | = t
t is obviously not negative. We know that s is positive, hence we can drop absolute value. We have s*t = t <=> {t = 0 AND s >0} {t > 0 AND s = 1}
INSUFF
(2) | st | = 7
1 * 7 = |1 * -7| = 7
INSUFF
Combine both. t cannot be 0, hence t > 0 and s = 1 (from A). s = 1 -> t = 7
Answer is C
(1) | st | = t
t is obviously not negative. We know that s is positive, hence we can drop absolute value. We have s*t = t <=> {t = 0 AND s >0} {t > 0 AND s = 1}
INSUFF
(2) | st | = 7
1 * 7 = |1 * -7| = 7
INSUFF
Combine both. t cannot be 0, hence t > 0 and s = 1 (from A). s = 1 -> t = 7
Answer is C