If m and n are integers, amd m>0>n, is m^n<1?
i) m is an even number
ii) n^2 > 1
So it appears as though the stem already says it all and there is no need of any more information. Please help!
Inequalities
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- kmittal82
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I dont think the question stem has all the information.
Consider m = 1 and n = -1 , in which case m ^ n = 1
For any other values of m and n, m ^ n will always be less than 1, but we still need to rule out the possibility of m = 1 and n = -1.
Consider m = 1 and n = -1 , in which case m ^ n = 1
For any other values of m and n, m ^ n will always be less than 1, but we still need to rule out the possibility of m = 1 and n = -1.
- kmittal82
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I think the answer is right, but there is a flaw in your argument.ov25 wrote:So..lets see
1) m>1 SUFF
2) n<-1 INSUFF
1/2^-5 = 2^5 = 32
and 2^-5 = 1/32
A right?
m cannot be 1/2, since m and n are both integers.
Statement 2 tells us that n is not equal to -1, but it doesnt say anything about m. If m is 1, then n could be anything and the result would be 1, which makes statement 2 insufficient. However, statement 1 says that m is greater than 1, so for any value of n, m ^ n will always be less than 1.