In the coordinate plane, a circle has center (2, -3) and passes through the point (5, 0).
What is the area of the circle?
A. 3pie
B. 3 sqrt 2 pie
C. 3 sqrt 3 pie
D. 9pie
E. 18pie
OA E
In the coordinate plane, a circle has center (2, -3)
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Hi ,
i got the way you did the sum ....but whats d logic behind it ? if u could let me know that!![Smile :-)](./images/smilies/smile.png)
Is there a formula for this ?
i got the way you did the sum ....but whats d logic behind it ? if u could let me know that!
![Smile :-)](./images/smilies/smile.png)
Is there a formula for this ?
- linkinpark
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Bhumika
formula for finding distance between (x,y) and (x1,y1) = square_root( (x-x1)^2 + (y-y1)^2 )
is the formula for finding distance between two points. we're told 2,-3 is center and that circle passes through other point. which means distance between center point and the other point is radiusace_gre wrote:( (x1-x2)^2 + (y1-y2)^2)^1/2
formula for finding distance between (x,y) and (x1,y1) = square_root( (x-x1)^2 + (y-y1)^2 )
530->480->580
when posting a question don't post OA(even masked) before some discussion.
when posting a question don't post OA(even masked) before some discussion.
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linkin is it sq rt (x-x1)^2 ... or ( (x1-x2)^2 + (y1-y2)^2)^1/2 ???
Can u gemme the exact formula ?
Can u gemme the exact formula ?
linkinpark wrote:Bhumikais the formula for finding distance between two points. we're told 2,-3 is center and that circle passes through other point. which means distance between center point and the other point is radiusace_gre wrote:( (x1-x2)^2 + (y1-y2)^2)^1/2
formula for finding distance between (x,y) and (x1,y1) = square_root( (x-x1)^2 + (y-y1)^2 )
- thephoenix
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the form isbhumika.k.shah wrote:linkin is it sq rt (x-x1)^2 ... or ( (x1-x2)^2 + (y1-y2)^2)^1/2 ???
Can u gemme the exact formula ?
linkinpark wrote:Bhumikais the formula for finding distance between two points. we're told 2,-3 is center and that circle passes through other point. which means distance between center point and the other point is radiusace_gre wrote:( (x1-x2)^2 + (y1-y2)^2)^1/2
formula for finding distance between (x,y) and (x1,y1) = square_root( (x-x1)^2 + (y-y1)^2 )
dis b/n two points a(x1,y1)and b(x2,y2) is
sqrt[(x1-x2)^2+(y1-y2)^2]
here x1=2 ; y1=-3
and x2=5 ; y2=0
hence r=3 rut 2
and area is 18 * pie
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Solution:bhumika.k.shah wrote:In the coordinate plane, a circle has center (2, -3) and passes through the point (5, 0).
What is the area of the circle?
A. 3pie
B. 3 sqrt 2 pie
C. 3 sqrt 3 pie
D. 9pie
E. 18pie
OA E
Because the circle passes through point (5,0) and has center (2,-3), we know that the distance between these points is the radius of the circle.
Since we are given the coordinates for each point, the easiest thing to do is to use the distance formula to determine the circle's radius. The distance formula is:
Distance= √[(x2 - x1)^2 + (y2 - y1)^2]
We are given two ordered pairs, so we can label the following:
x1 = 2
x2 = 5
y1 = -3
y2 = 0
When we plug these values into the distance formula, we have:
Distance= √[(5 - 2)^2 + (0 - (-3))^2]
Distance= √ [(3)^2 + (3)^2]
Distance= √ [9 + 9]
Distance = √ [18]
Distance = √9 x √2
Distance = 3 x √2
Thus, we know that the radius = 3 x √2.
Finally, we can use the radius to determine the area of the circle.
area = πr^2
area = π(3 x √2 )^2
area = π(9 x 2 )
area = 18Ï€
The answer is E
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Thanks for the formula and the clear breakdown!thephoenix wrote:the form isbhumika.k.shah wrote:linkin is it sq rt (x-x1)^2 ... or ( (x1-x2)^2 + (y1-y2)^2)^1/2 ???
Can u gemme the exact formula ?
linkinpark wrote:Bhumikais the formula for finding distance between two points. we're told 2,-3 is center and that circle passes through other point. which means distance between center point and the other point is radiusace_gre wrote:( (x1-x2)^2 + (y1-y2)^2)^1/2
formula for finding distance between (x,y) and (x1,y1) = square_root( (x-x1)^2 + (y-y1)^2 )
dis b/n two points a(x1,y1)and b(x2,y2) is
sqrt[(x1-x2)^2+(y1-y2)^2]
here x1=2 ; y1=-3
and x2=5 ; y2=0
hence r=3 rut 2
and area is 18 * pie
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