In an integer division operation, the divisor is x, the quotient is y, the dividend is z, and remainder is r. Is x > y?
(1) z = 151
(2) r = 11
OA C
Source: Veritas Prep
5-Day Free Trial
5-day free, full-access trial TTP
Available with Beat the GMAT members only code
MORE DETAILS
In an integer division operation, the divisor is x, the quot
This topic has expert replies
-
BTGmoderatorDC
- Moderator
- Posts: 7187
- Joined: Thu Sep 07, 2017 4:43 pm
- Followed by:23 members
Timer
00:00
Your Answer
A
B
C
D
E
Global Stats
GMAT/MBA Expert
-
Ian Stewart
- GMAT Instructor
- Posts: 2621
- Joined: Mon Jun 02, 2008 3:17 am
- Location: Montreal
- Thanked: 1090 times
- Followed by:355 members
- GMAT Score:780
Timer
00:00
Your Answer
A
B
C
D
E
Global Stats
You don't need to know what a "dividend" is on the GMAT, and if this were a real GMAT question it would declare that all of the numbers are positive.
In this question, we're dividing z by x, and getting a quotient of y and a remainder of r. So z = xy + r
Using either Statement alone, we really have no information that would let us compare x and y, so the answer is C or E.
Using both Statements together, we have 151 = xy + 11, so 140 = xy. It might seem this is not sufficient, but we know one more thing: we get a remainder of 11 when we divide z by x. That's only possible if we're dividing by something larger than 11. So x > 11, and since x and y are integers that multiply to 140, x is at least 14, and y is at most 10, and x > y. So the answer is C.
In this question, we're dividing z by x, and getting a quotient of y and a remainder of r. So z = xy + r
Using either Statement alone, we really have no information that would let us compare x and y, so the answer is C or E.
Using both Statements together, we have 151 = xy + 11, so 140 = xy. It might seem this is not sufficient, but we know one more thing: we get a remainder of 11 when we divide z by x. That's only possible if we're dividing by something larger than 11. So x > 11, and since x and y are integers that multiply to 140, x is at least 14, and y is at most 10, and x > y. So the answer is C.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com
ianstewartgmat.com
ianstewartgmat.com
Timer
00:00
Your Answer
A
B
C
D
E
Global Stats
Hi Ian,Ian Stewart wrote:You don't need to know what a "dividend" is on the GMAT, and if this were a real GMAT question it would declare that all of the numbers are positive.
In this question, we're dividing z by x, and getting a quotient of y and a remainder of r. So z = xy + r
Using either Statement alone, we really have no information that would let us compare x and y, so the answer is C or E.
Using both Statements together, we have 151 = xy + 11, so 140 = xy. It might seem this is not sufficient, but we know one more thing: we get a remainder of 11 when we divide z by x. That's only possible if we're dividing by something larger than 11. So x > 11, and since x and y are integers that multiply to 140, x is at least 14, and y is at most 10, and x > y. So the answer is C.
Isn't this E? x can equal 70 and y can equal 2.
