Data Sufficiency

In 1990 850 million movie tickets were sold in the United States. One fifth of those tickets were bought by people over the age of 50. Did people under the age of 20 buy more than 425 million movie tickets in 1990?

(1) In 1990, people under the age of 20 bought between two and three times as many tickets as were bought by people over the age of fifty.

(2) In 1990, people under the age of 20 spent $2.2 billion more on movie tickets than did people over the age of 50, with both groups spending an average (arithmetic mean) of $6 per ticket.

OA is B

Given : 170 million tickets bought by people over 50.
Question: People under age 20 buy > 425 million tickets ?

I have a doubt in B. So, here's my work:
Both groups spending an average of $6 per ticket. People under the age 20 spent a total of $2.2 billion on tickets. So,
2.2 Billion / $6 = (Approx) 366 million tickets. So, the answer is no, but s(2) is sufficient.

Total of 536.67 million tickets are bought, out of which 170 million are bought by people over 50 --> 536.67 - 170 = 366 million.

Please let me your analysis or correct me if i am wrong.

Thanks

Any idea how to approach this question.

Please

GMATGuruNY wrote: The statement in red does not accurately reflect the information in Statement 2.
Statement 2: People under the age of 20 spent $2.2 billion MORE on movie tickets than did people over the age of 50.
Here, the total amount spent by people under the age of 20 ≠ $2.2 billion.
The usage of MORE indicates that the total spent by people under the age of 20 was $2.2 billion GREATER than the total amount spent by people over the age of 50.

Thanks Mitch,

So, s(2) -->
Total spent by people over 50 = $6 * 170 million tickets = $1.02 Billion
Total spent by people under 20 = $1.02 Billion + $2.2 Billion = $3.22 Billion
$3.22 Billion/$6 = 536 million tickets
So s(2) is sufficient.

vinni.k wrote: So, s(2) -->
Total spent by people over 50 = $6 * 170 million tickets = $1.02 Billion
Total spent by people under 20 = $1.02 Billion + $2.2 Billion = $3.22 Billion
$3.22 Billion/$6 = 536 million tickets
So s(2) is sufficient.

Is this correct ?