if x and y are positive integers such that x = 8y + 12,

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If x and y are positive integers such that x = 8y + 12, what is the greatest common divisor of x and y?
(1) x = 12u, where u is an integer.
(2) y = 12z, where z is an integer.

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by puneetkhurana2000 » Sun Dec 16, 2012 3:10 pm
You can solve it using algebra, but i prefer to use some numbers as explained below:-

Statement 1) x = 12 u

So, for x to be a multiple of 12, we have (36,3) and (60,6) satisfy the eqn x = 8*y + 12. In these cases the HCF is 3 and 6 respectively. Not Sufficient!!!

Statement 2) y = 12 z

So, for y to be a multiple of 12, we have (12*9,12) and (12*17,24) and (12*25,36) and (12*33,48) satisfy the eqn x = 8*y + 12. In each case the HCF is 12. Sufficient!!!

Answer B.

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by GMATGuruNY » Sun Dec 16, 2012 8:55 pm
varun289 wrote:If x and y are positive integers such that x = 8y + 12, what is the greatest common divisor of x and y?
(1) x = 12u, where u is an integer.
(2) y = 12z, where z is an integer.
For many test-takers, the most efficient approach on test day would be to plug in.

Statement 1: x=12u, where u is an integer and x=8y+12.
In other words, x is a multiple of 12.
For x to be a multiple of 12, 8y must be a multiple of 12.

If y=3, then x = 8*3 + 12 = 36.
The GCD of 3 and 36 is 3.

If y=6, then x = 8*6 + 12 = 60.
The GCD of 6 and 60 is 6.

Since the GCD can be different values, INSUFFICIENT.

Statement 2: y=12z, where z is an integer and x=8y+12.
In other words, y is a multiple of 12.
Since we're looking for the GCD, view x in terms of its FACTORS.

If y=12, then x = 8(12) + 12 = 12(8+1) = 12*9.
The GCD of 12 and 12*9 is 12.

If y=24, then x = 8(24) + 12 = 12(8*2 + 1) = 12*17.
The GCD of 24 and 12*17 is 12.

I'm almost convinced: the GCD is 12.
Maybe one more just to be sure:

If y=36, then x = 8(36) + 12 = 12(8*3 + 1) = 12*25.
The GCD of 36 and 12*25 is 12.
SUFFICIENT.

The correct answer is B.
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by Brent@GMATPrepNow » Mon Dec 17, 2012 7:51 am
varun289 wrote:If x and y are positive integers such that x = 8y + 12, what is the greatest common divisor of x and y?
(1) x = 12u, where u is an integer.
(2) y = 12z, where z is an integer.
Target question: What is the greatest common divisor of x and y?

Given: x = 8y + 12

Statement 1: x = 12u, where u is an integer.
There are several pairs of values that satisfy the given conditions. Here are two:
Case a: x=36 and y=3, in which case the GCD of x and y is 3
Case b: x=60 and y=6, in which case the GCD of x and y is 6
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: y = 12z, where z is an integer.
If y = 12z and x = 8y + 12, then we can replace y with 12z to get:
x = 8(12z) + 12, which means x = 96z + 12, which means x = 12(8z + 1) [if we factor]

So, what is the GCD of 12z and 12(8z + 1)?
Well, we can see that they both share 12 as a common divisor, but what about z and 8z+1?
Well, there's a nice rule that says: The GCD of n and kn+1 is always 1 (if n and k are positive integers)
So, the GCD of z and 8z+1 is 1, which means the GCD of 12z and 12(8z + 1) is 12.
This means that the GCD of x and y is 12
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer = B


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by alexander.vien » Wed Jan 02, 2013 6:55 pm
GCD or Greatest Common Divisor = GCF or Greatest Common Factor

Whenever the word "divisor" is seen in a GMAT question, it can be replaced with "factor" - since factors and multiples are what most study when preparing for the GMAT.

Just wanted to clarify since this constantly confuses me!

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by Brent@GMATPrepNow » Wed Jan 02, 2013 7:05 pm
Yes, "factor" is the same as "divisor"
In fact, there are many ways to express the concepts of divisors and factors.

For example, "y is a factor of x" can be reworded in the following ways:
"y is a divisor of x"
"x is divisible by y"
"When x is divided by y the remainder is zero"
"x equals ky for some integer k"
"x is a multiple of y"
or even, "y is hiding in the prime factorization of x"

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by alexander.vien » Wed Jan 16, 2013 12:16 pm
Also want to point out for this question that a quick way of knowing B is sufficient is the rule that states that if two numbers are both multiplies of a certain number, adding or subtracting them will generate an answer that is a multiple of that same number.

For example: 35 (multiple of 7) - 21 (multiple of 7) = 14 (multiple of 7)

So, we can apply this rule to statement 2.

if y = 12z, then x = 96z + 12 -> in other words, y is a multiple of 12, so a multiple of 12 added together with a multiple of 12 must be a multiple of 12! So, x is a multiple of 12 as well. Knowing that x will always be greater than y, means that 12 will always be the greatest common factor of x and y.