If x = a, y = 2b, z = 3c, and x : y : z = 1 : 2 : 3, then (x + y + z)/(a + b + c) =
(A) 1/3
(B) 1/2
(C) 2
(D) 3
(E) 6
Answer: C
Source: Nova
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If x = a, y = 2b, z = 3c, and x : y : z = 1 : 2 : 3, then (x + y + z)/(a + b + c)
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BTGModeratorVI
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Brent@GMATPrepNow
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One approach is to find values for a, b, c, x, y and z that satisfy the given information.BTGModeratorVI wrote: ↑Mon Sep 14, 2020 8:45 amIf x = a, y = 2b, z = 3c, and x : y : z = 1 : 2 : 3, then (x + y + z)/(a + b + c) =
(A) 1/3
(B) 1/2
(C) 2
(D) 3
(E) 6
Answer: C
Source: Nova
GIVEN: x : y : z = 1 : 2 : 3
So, it COULD be the case that x = 1, y = 2 and z = 3
GIVEN: x = a, y = 2b, z = 3c
If x = 1, then a = 1
If y = 2, we can say that 2 = 2b, which means b = 1
If z = 3, we can say that 3 = 3c, which means c = 1
So, (x + y + z)/(a + b + c) = (1 + 2 + 3)/(1 + 1 + 1)
= 6/3
= 2
Answer: C
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Brent
Brent Hanneson - Creator of GMATPrepNow.com
