If $$x=3y=4z$$ Which of the following must equal 6x?
$$I.18y$$
$$II.3y+20z$$
$$III.\frac{(4y+10z)}{3}$$
(A) I only
(B) II only
(C) III only
(D) I and II only
(E) I and III only
The OA is D.
I'm confused with this PS question. Please, can any expert assist me with it? Thanks in advanced.
Hi LUANDATO,
Let's take a look at your question.
$$x=3y=4z$$
We need to check which of the given expressions are equivalent to 6x. Let's evaluate them one by one.
$$I. 18y$$
Let's rewrite y in terms of x.
Since,
$$x\ =\ 3y$$ $$y=\frac{x}{3}$$
Replace value of y in 18y, we get,
$$=18\left(\frac{x}{3}\right)$$
$$=6x$$
$$II.3y+20z$$
From x=3y=4z, we get,
$$y=\frac{x}{3},\ z=\frac{x}{4}$$
Plugin the values in II, we get:
$$=3\left(\frac{x}{3}\right)+20\left(\frac{x}{4}\right)$$
$$=x+5x=6x$$
$$III.\frac{(4y+10z)}{3}$$
Replace values of y and z, we get
$$=\frac{4\left(\frac{x}{3}\right)+10\left(\frac{x}{4}\right)}{3}$$
$$=\frac{\frac{4x}{3}+\frac{5x}{2}}{3}$$
$$=\frac{\frac{8x+15x}{6}}{3}$$
$$=\frac{23x}{6\times3}=\frac{23x}{18}$$
Therefore, only I and II are equal to 6x.
Hence, Option
D is correct.
Hope it helps.
I am available if you'd like any follow up.
