If x^2=x+1, then x^3=?

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If x^2=x+1, then x^3=?

by Max@Math Revolution » Mon Sep 12, 2016 3:52 pm
If x^2=x+1, then x^3=?
A. 3x+2
B. 3x-2
C. 2x+1
D. 2x-3
E. 3x+4

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by Humblejohny » Tue Sep 13, 2016 6:40 am
Ans C
given x^2 = x+ 1

bring to left x^2-x-1 = 0
multiply by x both sides, x(x^2-x-1)=0
x^3-x^2-x=0 --> x^3 = x^2+1, substitute x^2 value now we get x^3 = 2x+1

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by MBA Challengers » Wed Sep 14, 2016 5:07 am
Start with multiplying both sides by x.
Thus, x^3 = x^2 + x
Now, substitute the original value of x^2 in the equation above:
x^3 = (x + 1) + x
Thus, x ^ 3 = 2x + 1. The answer is C.
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by GMATGuruNY » Thu Sep 15, 2016 6:34 am
Max@Math Revolution wrote:If x^2=x+1, then x^3=?
A. 3x+2
B. 3x-2
C. 2x+1
D. 2x-3
E. 3x+4
Alternate approach:

x²=x+1 implies that the square of x is equal only to one more than x.
Thus, the roots of this equation must be very small.
If we test x=-1, x=-1/2, x=0, x=1/2 and x=1 in the given equation, the two sides are closest in value when x=-1/2.
Thus, one of the roots must be close to -1/2.
If x=-1/2, then x³ = -1/8.
Implication:
The correct answer choice must yield a value close to -1/8 when x=-1/2.
The value yielded by C is closest to -1/8:
2x+1 = (2)(-1/2) + 1 = 0.

The correct answer is C.
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