Hello,
Can you please help with solving Statement2 ?
If vm is not equal to 0, is vm > 0?
1) (v^2)m = v(m^2)
2) |m|v = |v|m
OA: D
1) vvm = vmm
=> v = m
=> vm > 0 . Suff.
2) |m|v = |v|m
=> |m|/|v| = m/v
However, I was not sure how to proceed from here. Can you please assist?
Thanks a lot,
Sri
If vm is not equal to 0, is vm > 0?
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You're almost there, Sri.gmattesttaker2 wrote:Hello,
Can you please help with solving Statement2 ?
If vm is not equal to 0, is vm > 0?
1) (v^2)m = v(m^2)
2) |m|v = |v|m
OA: D
1) vvm = vmm
=> v = m
=> vm > 0 . Suff.
2) |m|v = |v|m
=> |m|/|v| = m/v
However, I was not sure how to proceed from here. Can you please assist?
Thanks a lot,
Sri
If |m|/|v| = m/v then we know that m/v is positive.
If m/v is positive, then vm is also positive.
Cheers,
Brent
GMAT/MBA Expert
- Brent@GMATPrepNow
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The important rule at play here is that, if the QUOTIENT of two numbers is positive, then the PRODUCT of those same two numbers must also be positive.gmattesttaker2 wrote:Hello,
Can you please help with solving Statement2 ?
If vm is not equal to 0, is vm > 0?
1) v²m = vm²
2) |m|v = |v|m
For example, 6/3 is positive, and (6)(3) is also positive
Likewise, (-8)/(-4) is positive, and (-8)(-4) is also positive
Target question: Is vm positive?
Given: vm ≠0
In other words, v ≠0 and m ≠0
Statement 1: v²m = vm²
Take v²m = vm²
Divide both sides by v² to get: m = (vm²)/v²
Divide both sides by v to get: m/v = m²/v²
IMPORTANT: If v ≠0 and m ≠0, then v² is positive and m² is positive.
So, we get: m/v = (positive)/(positive)
In other words, m/v = some positive value
By the red rule above, we can conclude that mv is positive
Since we can answer the target question with certainty, statement 1 is SUFFICIENT
Statement 2: |m|v = |v|m
Take |m|v = |v|m
Divide both sides by m to get: (|m|v)/m = |v|
Divide both sides by |m| to get: v/m = |v|/|m|
IMPORTANT: If v ≠0 and m ≠0, then |v| is positive and |m| is positive.
So, we get: v/m = (positive)/(positive)
In other words, v/m = some positive value
By the red rule above, we can conclude that mv is positive
Since we can answer the target question with certainty, statement 2 is SUFFICIENT
Answer = D
Cheers,
Brent
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Hello Brent,Brent@GMATPrepNow wrote:The important rule at play here is that, if the QUOTIENT of two numbers is positive, then the PRODUCT of those same two numbers must also be positive.gmattesttaker2 wrote:Hello,
Can you please help with solving Statement2 ?
If vm is not equal to 0, is vm > 0?
1) v²m = vm²
2) |m|v = |v|m
For example, 6/3 is positive, and (6)(3) is also positive
Likewise, (-8)/(-4) is positive, and (-8)(-4) is also positive
Target question: Is vm positive?
Given: vm ≠0
In other words, v ≠0 and m ≠0
Statement 1: v²m = vm²
Take v²m = vm²
Divide both sides by v² to get: m = (vm²)/v²
Divide both sides by v to get: m/v = m²/v²
IMPORTANT: If v ≠0 and m ≠0, then v² is positive and m² is positive.
So, we get: m/v = (positive)/(positive)
In other words, m/v = some positive value
By the red rule above, we can conclude that mv is positive
Since we can answer the target question with certainty, statement 1 is SUFFICIENT
Statement 2: |m|v = |v|m
Take |m|v = |v|m
Divide both sides by m to get: (|m|v)/m = |v|
Divide both sides by |m| to get: v/m = |v|/|m|
IMPORTANT: If v ≠0 and m ≠0, then |v| is positive and |m| is positive.
So, we get: v/m = (positive)/(positive)
In other words, v/m = some positive value
By the red rule above, we can conclude that mv is positive
Since we can answer the target question with certainty, statement 2 is SUFFICIENT
Answer = D
Cheers,
Brent
Thanks for your awesome explanation and for explaining everything so clearly. Many thanks again.
Best Regards,
Sri