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by mj78ind » Sun Jun 20, 2010 7:19 am
Area of the equilateral triangle = (t^2)*(1/4)*(sqrt3) and the area of the square = s^2

equating the two, t^2(sqrt3)/4 = s^2 hence (t/s)^2 = 4/sqrt(3) or t/s = (4/3^(1/2))^(1/2)

which seems complicated but in fact comes to t/s = 2/(3)^1/4

Hope it helped.
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by papgust » Sun Jun 20, 2010 7:20 am
I suggest that you search the question first before you post,

https://www.beatthegmat.com/areas-and-ratios-t29764.html
Download GMAT Math and CR questions with Solutions from Instructors and High-scorers:
https://www.beatthegmat.com/download-gma ... 59366.html

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by ssuarezo » Sun Jun 20, 2010 8:18 am
papgust wrote:I suggest that you search the question first before you post,

https://www.beatthegmat.com/areas-and-ratios-t29764.html
Hi Papgust,
Actually, I did it, for the last posts ... anyway I'm going to check the other posts ...

Thanks mj78ind for your quick answer.

Silvia.
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by Patrick_GMATFix » Sun Jun 20, 2010 3:12 pm
Hi Silvia,

You may find it worthwhile to memorize the formula for the area of an equilateral triangle of side t. The area is t^2*root(3)/4. We're told that this area is the same as the area of the square (s^2). Thus we can equate the two values and manipulate the equation until we isolate t/s.

If you perform the simplification correctly, you will find that t/s equals answer D. This is the OA.

A detailed step-by-step solution, a 30-second hack, and a video solution are available at GMATPrep Question 1111. To practice similar questions, set topics='Geometry' and difficulty='700+' in the Drill Generator

Hope you kick butt tomorrow!
-Patrick
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