A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time . On the way, however the train lost about 12.5 minutes while stopping at the stations. The speed of the car is
A 100 km/hr
B 110 km/hr
C 120 km/hr
D 130 km/hr
E 150 km/hr
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vaibhav101
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We can let r = the speed of the car, and thus 1.5r = the speed of the train. Since the actual travel time of the train (i.e., not including the stopping time) is 12.5/60 = 25/120 = 5/24 hour less than the travel time of the car, we can create the equation:vaibhav101 wrote:A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time . On the way, however the train lost about 12.5 minutes while stopping at the stations. The speed of the car is
A 100 km/hr
B 110 km/hr
C 120 km/hr
D 130 km/hr
E 150 km/hr
75/r = 75/(1.5r) + 5/24
Multiplying the equation by 24r, we have:
1800 = 1200 + 5r
600 = 5r
120 = r
Answer: C
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