stevecultt wrote:If s is the sum of all integers from 1 to 30, inclusive, what is the sum of all the factors of s?

(A) 303
(B) 613
(C) 675
(D) 737
(E) 768

OA E

We have 30 consecutive integers starting from 1, thus the median of the numbers would be (1+30)/2 = 31/2. Since consecutive integers from 1 to 30 form an even spaced set, the median of the set = mean of the set.

Thus sum s = Mean x number of integers = (31/2) x 30 = 15x31 = 3x5x31;

Thus, the prime factors of s are: 3, 5 and 31.

Thus, the factors of s are: 1; 3; 5; 31; 3 x 5 ƒ= 15; 3 x 31 ƒ= 93; 5 x 31 ƒ= 155; and 3 x 5 x 31 =ƒ 465.

Thus, the sum of all the factors of s ƒ 1 +‚ 3 +‚ 5 +‚ 31 +‚ 15 ‚+‚ 93 ‚+ 155 ‚+ 465 ƒ= 768.

The correct answer: E

Hope this helps!

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stevecultt wrote: ↑

Mon Jun 12, 2017 4:20 am

If s is the sum of all integers from 1 to 30, inclusive, what is the sum of all the factors of s?

(A) 303
(B) 613
(C) 675
(D) 737
(E) 768

OA E

The sum of all integers from 1 to 30, inclusive, is 30(30 + 1) / 2 = 15(31) = 3 x 5 x 31 = 465.

Recall that the total number of factors of a number is calculated by adding 1 to the exponent of each prime factor of the number and then multiplying those sums together. Since s = 3^1 x 5^1 x 31^1, then 465 has (1 + 1) x (1 + 1) x (1 + 1) = 8 factors. These 8 factors are:

1, 465
3, 155
5, 93
15, 31

Therefore, the sum of all the factors of s is 1 + 3 + 5 + 15 + 31 + 93 + 155 + 465 = 768.

Answer: E