In the formula V = 1/(2r)^3, if r is halved then V is multiplied by
A) 64
B) 8
C) 1
D) 1/8
E) 1/64
if r is halved V is multiplied by
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A quick approach here is to plug in a "nice" number.BlueDragon2010 wrote:In the formula V = 1/(2r)³, if r is halved then V is multiplied by
A) 64
B) 8
C) 1
D) 1/8
E) 1/64
Let's plug in r = 1. We get V = 1/[(2)(1)]³ = 1/8
Now let's see what happens when we HALVE r. In other words, we'll plug in r = 1/2.
We get V = 1/[(2)(1/2)]³ = 1
So, when r = 1, V = 1/8, and when r = 1/2, V = 1.
So, when we halve r, V is multiplied by 8
Answer = B
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Brent
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I might plug in values (r=1 --> 1/2 for instance), or just replace r with r/2 and compare the original V to the new V. The answer is B. I go through the question in detail in the full solution below (taken from the GMATFix App).
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Hi BlueDragon2010,
This question is perfect for TESTing Values, as Brent's solution showcases.
If you'd rather do algebra, here's how you could solve this problem:
V = 1/(2r)^3
V = 1/8r^3
This is the "starting value"
The question asks us to HALVE the value of r, so we'd then start with this....
V = 1/(r)^3
V = 1/r^3
Compare the denominators of both fractions and you'll see that the denominator went from 8r^3 to r^3, meaning that the denominator was divided by 8. When you divide the denominator of a fraction by 8, the OVERALL fraction becomes 8 times BIGGER.
Final Answer: B
GMAT assassins aren't born, they're made,
Rich
This question is perfect for TESTing Values, as Brent's solution showcases.
If you'd rather do algebra, here's how you could solve this problem:
V = 1/(2r)^3
V = 1/8r^3
This is the "starting value"
The question asks us to HALVE the value of r, so we'd then start with this....
V = 1/(r)^3
V = 1/r^3
Compare the denominators of both fractions and you'll see that the denominator went from 8r^3 to r^3, meaning that the denominator was divided by 8. When you divide the denominator of a fraction by 8, the OVERALL fraction becomes 8 times BIGGER.
Final Answer: B
GMAT assassins aren't born, they're made,
Rich