If quadrilaterals ABCD and ADEF have the same areas, is AF&a

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GMATH practice exercise (Quant Class 15)

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If quadrilaterals ABCD and ADEF have the same areas, is AF > 28 ?

(1) EF = 10
(2) CE = 24

Answer: [spoiler]______(C)__[/spoiler]
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
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fskilnik@GMATH wrote:GMATH practice exercise (Quant Class 15)

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If quadrilaterals ABCD and ADEF have the same areas, is AF > 28 ?

(1) EF = 10
(2) CE = 24
Image

$${S_{{\mathop{\rm ABCD}\nolimits} }} = {S_{{\rm{ADEF}}}} = {S_{{\rm{ADEG}}}} + {S_{{\rm{AGF}}}}\,\,\,\,\,\left( * \right)$$
$$AF\,\,\mathop > \limits^? \,\,28$$
$$\left( 1 \right)\,\,\left\{ \matrix{
\,{\rm{image}}\,\,{\rm{left}}:\,\,\left( * \right)\,\,4 \cdot 6 = 3 \cdot 6 + {{3 \cdot 4} \over 2}\,\,\,\,\, \Rightarrow \,\,\,\,{\rm{viable}}\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\rm{NO}}} \right\rangle \hfill \cr
\,{\rm{image}}\,\,{\rm{right}}:\,\,\left( * \right)\,\,x \cdot 6 = 28 \cdot 6 + {{28 \cdot 4} \over 2}\,\,\,\,\, \Rightarrow \,\,\,\,{\rm{viable}}\,\,\,\left( {x = {{28 \cdot 8} \over 6} > 0} \right)\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\rm{YES}}} \right\rangle \hfill \cr} \right.$$
$$\left( 2 \right)\,\,\left\{ \matrix{
\,{\rm{image}}\,\,{\rm{left}}:\,\,\left( * \right)\,\,18 \cdot y = 6 \cdot y + {{6 \cdot 4} \over 2}\,\,\,\,\, \Rightarrow \,\,\,\,{\rm{viable}}\,\,\,\,\left( {y = 1 > 0} \right) \Rightarrow \,\,\,\,\left\langle {{\rm{NO}}} \right\rangle \hfill \cr
\,{\rm{image}}\,\,{\rm{right}}:\,\,\left( * \right)\,\,18 \cdot y = 6 \cdot y + {{6 \cdot 28} \over 2}\,\,\,\,\, \Rightarrow \,\,\,\,{\rm{viable}}\,\,\,\left( {y = 7 > 0} \right)\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\rm{YES}}} \right\rangle \hfill \cr} \right.$$
$$\left( {1 + 2} \right)\,\,{\rm{Extremal}}\,\,{\rm{Scenario}}\,\,\,\left( {\left( * \right)\,\,{\rm{ignored}}} \right)\,\,:\,\,A{F_{\,{\rm{ExtScen}}}}\,\,\mathop < \limits^{{\rm{near}}} \,\,13 \cdot 2 = 26$$
$$ \Rightarrow \,\,AF < \,\,A{F_{\,{\rm{ExtScen}}}} < 28\,\,\,\, \Rightarrow \,\,\,\,{\rm{SUFF}}.$$

The correct answer is (C).

We follow the notations and rationale taught in the GMATH method.

Regards,
Fabio.

POST-MORTEM: (1+2) It is possible to prove that AF < 16. See:   <span text-bold"><a href="https://gmatclub.com/forum/if-quadrilat ... l#p2243965" target="_blank" class="text-info">Shobhit7´s argument</a></span>
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br