If n is the product of the integers from 1 to 8, inclusive, how many different prime factors greater than 1 does n have?
A) Four
B) Five
C) Six
D) Seven
E) Eight
The OA is A.
Please, can any expert explain this PS question for me? I have many difficulties to understand why that is the correct answer. Thanks.
If n is the product of the integers from 1 to 8...
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Hi Swerve,If n is the product of the integers from 1 to 8, inclusive, how many different prime factors greater than 1 does n have?
A) Four
B) Five
C) Six
D) Seven
E) Eight
The OA is A.
Please, can any expert explain this PS question for me? I have many difficulties to understand why that is the correct answer. Thanks.
Let's take a look at your question.
n is the product of the integers from 1 to 8, inclusive.
$$n=1\times2\times3\times4\times5\times6\times7\times8$$ $$n=1\times2\times3\times\left(2\times2\right)\times5\times\left(2\times3\right)\times7\times\left(2\times2\times2\right)$$ $$n=1\times2\times2\times2\times2\times2\times2\times2\times3\times3\times5\times7$$
We can see that the product n has four different prime factors, 2, 3, 5, 7.
Therefore, Option A is correct.
Hope it helps.
I am available if you'd like any follow up.
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n = (1)(2)(3)(4)(5)(6)(7)(8)swerve wrote:If n is the product of the integers from 1 to 8, inclusive, how many different prime factors greater than 1 does n have?
A) Four
B) Five
C) Six
D) Seven
E) Eight
= (1)(2)(3)(2)(2)(5)(2)(3)(7)(2)(2)(2)
The prime factors are 2, 3, 5 and 7
Answer: A
Cheers,
Brent