BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

If mx = m, then what is the value of m?

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 2276
Joined: Sat Oct 14, 2017 6:10 amFollowed by: 3 members
by VJesus12 » Sat Feb 17, 2018 8:02 am
If mx = m, then what is the value of m?

(1) m has only one multiple.
(2) x has only one distinct factor.

The OA is A.

Why is not sufficient the statement (2)? Experts, may you help me to solve this DS question? Thanks in advanced.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3008
Joined: Mon Aug 22, 2016 6:19 amFollowed by: 34 members
Location: Grand Central / New York
Thanked: 470 times

by Jay@ManhattanReview » Fri Mar 09, 2018 12:18 am
VJesus12 wrote:If mx = m, then what is the value of m?

(1) m has only one multiple.
(2) x has only one distinct factor.

The OA is A.

Why is not sufficient the statement (2)? Experts, may you help me to solve this DS question? Thanks in advanced.
Given: mx = m

We have to find out the value of m.

Let's take each statement one by one.

(1) m has only one multiple.

0 is the only number that has only one multiple, thus m = 0. Sufficient. Sufficient. Note multiples of 1 are 1, 2, 3, ...

(2) x has only one distinct factor.

1 is the only number that has only one distinct factor, thus x = 1, but we cannot get the unique value m. m can take any value; for example 0*1 = 0; 10*1 = 10, etc. Insufficient.

The correct answer: A

Hope this helps!

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Jakarta | Nanjing | Berlin | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2898
Joined: Thu Sep 07, 2017 2:49 pmFollowed by: 5 members
Thanked: 6 times

by Vincen » Fri Mar 09, 2018 7:27 am
Hello Vjesus12.

I'd solve it as follows:

(1) m has only one multiple.

This implies that, given any integers x and y, we get that $$m\cdot x=m\cdot y\ \ \ \ \forall\ x,y\ \in R.$$ Now, the only number that satisfy this condition is m=0.

Hence, this statement is Sufficient.

(2) x has only one factor.

This implies that the prime factorization of x is only one number, and the unique number that satisfy this condition is x=1.

Therefore, we have that mx=m implies that m=m. But this doesn't tell us what is the value of m. INSUFFICIENT.

Because of this, the answer is the option A.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1