BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

If f(x)=1-(1/x), then f(f(f(x)))=?

Expert replies
by Max@Math Revolution » Thu Dec 27, 2018 11:13 pm

Timer

00:00

Answers

A

0%

B

0%

C

0%

D

0%

E

0%

Stats

Difficulty

0% CorrectAvg —

0% IncorrectAvg —

[Math Revolution GMAT math practice question]

If f(x)=1-(1/x), then f(f(f(x)))=?

A. x
B. 1/x
C. 1/x+1
D. -1/x+1
E. x/x+1
Join the discussion
Source: — Problem Solving |

answer

by Manasa3190 » Fri Dec 28, 2018 7:56 pm
f(x) = 1-(1/x)
f(x) = (x-1)/x

f(f(x)) implies substituting f(x) as x in above expression
f(f(x)) = (1-(1/x) -1 )/(1-(1/x))
f(f(x)) = -1/(x-1)

f(f(f(x))) = f(-1/(x-1))
Substituting 'x' as -1/(x-1) in f(x)
f(f(f(x))) = 1 - (1/(-1/(x-1)))
f(f(f(x))) = 1 + x -1
f(f(f(x))) = x
So, Option A is correct
Join the discussion

by Max@Math Revolution » Sun Dec 30, 2018 5:18 pm
=>

f(x) = 1 - 1/x = (x-1)/x
f(f(x)) = 1 - 1/f(x) = 1 - x/(x-1) = (x-1-x)/(x-1) = - 1/(x-1)
f(f(f(x))) = 1 - 1/f(f(x)) = 1 - ( - (x-1)) = 1 + x - 1 = x

Therefore, the answer is A.
Answer: A
Join the discussion

by GMATGuruNY » Mon Dec 31, 2018 11:07 am
Max@Math Revolution wrote:[Math Revolution GMAT math practice question]

If f(x)=1-(1/x), then f(f(f(x)))=?

A. x
B. 1/x
C. 1/x+1
D. -1/(x+1)
E. x/(x+1)
Let x=2 and apply the function three times:
f(2) = 1 - 1/2 = 1/2.
f(1/2) = 1 - 1/(1/2) = -1.
f(-1) = 1 - (1/-1) = 2.

The correct answer must yield a value of 2 when x=2.
Only A works.

The correct answer is A.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion