If both 5^2 and 3^3 are factors of n x 2^5 x 6^2 x 7^3 , what is the smallest possible positive value of n?
A) 25
B) 27
C) 45
D) 75
E) 125
I am having trouble with this question....
I keep thinking it is A...
the correct answer is... D
Please help! Thanks!
If both 5 squared and 3 cubed...
This topic has expert replies
-
- Junior | Next Rank: 30 Posts
- Posts: 26
- Joined: Mon Feb 02, 2009 4:45 pm
- Thanked: 1 times
-
- Junior | Next Rank: 30 Posts
- Posts: 25
- Joined: Fri Jan 23, 2009 11:57 am
- Location: Minneapolis
- Thanked: 1 times
Hello,
Please post this question is problem solving. This is Data Sufficiency section. Anyhow answer is D.
Raj.
Please post this question is problem solving. This is Data Sufficiency section. Anyhow answer is D.
Raj.
Raj Peddisetty
-
- Junior | Next Rank: 30 Posts
- Posts: 26
- Joined: Mon Feb 02, 2009 4:45 pm
- Thanked: 1 times
n x 2^5 x 6^2 x 7^3 can be written as
n x 2^5 x (3 x 2)^2 x 7^3
= n x 2^7 x 3^2 x 7^3
This should contain atleast 2 factors of 5 (5^2) and 3 factors of 3(3^3). Since the number already has 2 factors of 3, the smallest possible value of n is 5^2 x 3 = 75
n x 2^5 x (3 x 2)^2 x 7^3
= n x 2^7 x 3^2 x 7^3
This should contain atleast 2 factors of 5 (5^2) and 3 factors of 3(3^3). Since the number already has 2 factors of 3, the smallest possible value of n is 5^2 x 3 = 75
-
- Junior | Next Rank: 30 Posts
- Posts: 25
- Joined: Fri Jan 23, 2009 11:57 am
- Location: Minneapolis
- Thanked: 1 times
Hi houston,
I am sorry if you were offended. I just wanted to inform you that this section is for data sufficiency only. I felt it was more appropriate not to mix questions. thats it.....take it easy....
cheers...
I am sorry if you were offended. I just wanted to inform you that this section is for data sufficiency only. I felt it was more appropriate not to mix questions. thats it.....take it easy....
cheers...
Raj Peddisetty