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If ab not equal to 0, then \(a^{-1}+b^{-1}=\)

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by AAPL » Tue Oct 06, 2020 6:37 pm
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If ab not equal to 0, then \(a^{-1}+b^{-1}=\)

A. a+b
B. -(a+b)
C. 1/(a+b)
D. 2/(a+b)
E. (a+b)/ab

OA E
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Re: If ab not equal to 0, then \(a^{-1}+b^{-1}=\)

by Neha sharma » Wed Oct 07, 2020 5:10 am
=1/a+1/b
=(b+a)/ab

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Re: If ab not equal to 0, then \(a^{-1}+b^{-1}=\)

by Scott@TargetTestPrep » Sat Oct 10, 2020 2:15 pm
AAPL wrote: ↑
Tue Oct 06, 2020 6:37 pm
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If ab not equal to 0, then \(a^{-1}+b^{-1}=\)

A. a+b
B. -(a+b)
C. 1/(a+b)
D. 2/(a+b)
E. (a+b)/ab

OA E
Solution:

The common denominator is ab. Simplifying, we have:

1/a + 1/b = b/(ab) + a/(ab) = (a + b)/(ab)

Answer: E

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