If a large pizza has a radius that is 30% larger that that of a medium pizza, what is the percent increase in area between a medium and a large pizza?
a) 30
b) 36
c) 60
d) 69
e) 90
The OA id d.
I need some help here. Experts, can clarify to me how to solve this PS question?
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If a large pizza has a radius that is 30% larger
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Hi M7MBA,
We're told that a large pizza has a radius that is 30% larger that that of a medium pizza. We're asked for the percent increase in AREA between a medium and a large pizza. This question can be solved by TESTing VALUES.
IF....
The radius of a medium pizza is 10, then it's area = (pi)(10^2) = 100pi....
then the radius of a large pizza would be 13, so it's area = (pi)(13^2) = 169pi....
Percentage Change = (New - Old)/(Old) = (169pi - 100pi)/(100pi) = 69/100 = a 69% increase in area
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
We're told that a large pizza has a radius that is 30% larger that that of a medium pizza. We're asked for the percent increase in AREA between a medium and a large pizza. This question can be solved by TESTing VALUES.
IF....
The radius of a medium pizza is 10, then it's area = (pi)(10^2) = 100pi....
then the radius of a large pizza would be 13, so it's area = (pi)(13^2) = 169pi....
Percentage Change = (New - Old)/(Old) = (169pi - 100pi)/(100pi) = 69/100 = a 69% increase in area
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
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Vincen
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Hello M7MBA.
Let's suposse that the radius of the medium pizza is equal to r. This implies that the radius of the large pizza is r+0.3r=1.3r.
Now, the area of the medium pizza is $$\pi\cdot r^2$$ and the radius of the large pizza is $$\pi\cdot (1.3r)^2=1.69\pi\cdot r^2.$$ Therefore, the difference between them is $$1.69\pi\cdot r^2 - \pi\cdot r^2\ =\ 0.69\pi\cdot r^2.$$ Now, we have to find what percent represents this to the area of the medium pizza.
$$\pi\cdot r^2----------100\%$$ $$0.69\pi\cdot r^2----------x\%$$ Hence $$x=69\%.$$ Thus, the answer is d .
Let's suposse that the radius of the medium pizza is equal to r. This implies that the radius of the large pizza is r+0.3r=1.3r.
Now, the area of the medium pizza is $$\pi\cdot r^2$$ and the radius of the large pizza is $$\pi\cdot (1.3r)^2=1.69\pi\cdot r^2.$$ Therefore, the difference between them is $$1.69\pi\cdot r^2 - \pi\cdot r^2\ =\ 0.69\pi\cdot r^2.$$ Now, we have to find what percent represents this to the area of the medium pizza.
$$\pi\cdot r^2----------100\%$$ $$0.69\pi\cdot r^2----------x\%$$ Hence $$x=69\%.$$ Thus, the answer is d .
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Scott@TargetTestPrep
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We can let the radius of the medium pizza = 10, and thus the radius of the large pizza = 13. Therefore, we have:M7MBA wrote:If a large pizza has a radius that is 30% larger that that of a medium pizza, what is the percent increase in area between a medium and a large pizza?
a) 30
b) 36
c) 60
d) 69
e) 90
Area of medium pizza = 100Ï€
Area of large pizza = 169Ï€
Using the percent change formula: (New - Old)/Old x 100, we obtain:
(169Ï€ - 100Ï€)/100Ï€ x 100 = 69/100 = 69%
Answer: D
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