If a, b, c, d, e are consecutive positive integers such that

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GMATinsight: Legendary Member; Posts: 1100; Joined: Sat May 10, 2014 11:34 pmFollowed by: 24 members; Location: New Delhi, India; Thanked: 205 times

by GMATinsight » Sat Sep 29, 2018 10:18 pm

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If a, b, c, d, e are consecutive positive integers such that a<b<c<d<e, then what is the positive difference between averages of Set (b, c, d, e) and (a, b, c, d)

A) 0.25
B) 0.5
C) 0.75
D) 1
E) 1.5

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Source: Beat The GMAT — Problem Solving | Sat Sep 29, 2018 10:18 pm

GMATGuruNY: GMAT Instructor; Posts: 15539; Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members; Location: New York, NY; Thanked: 13060 times; GMAT Score:790

by GMATGuruNY » Sun Sep 30, 2018 3:16 am

GMATinsight wrote:If a, b, c, d, e are consecutive positive integers such that a < b < c < d < e, then what is the positive difference between averages of Set (b, c, d, e) and (a, b, c, d)

A) 0.25
B) 0.5
C) 0.75
D) 1
E) 1.5

For any set of consecutive integers, average = median.

Let the five integers = 1, 2, 3, 4, 5.
Average of 2, 3, 4 and 5 = 3.5.
Average of 1, 2, 3, and 4 = 2.5.
Difference between the averages = 3.5 - 2.5 = 1.

The correct answer is D.

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by Scott@TargetTestPrep » Sat Oct 13, 2018 5:37 pm

GMATinsight wrote:If a, b, c, d, e are consecutive positive integers such that a<b<c<d<e, then what is the positive difference between averages of Set (b, c, d, e) and (a, b, c, d)

A) 0.25
B) 0.5
C) 0.75
D) 1
E) 1.5

We see that b = a + 1, c = a + 2, d = a + 3 and e = a + 4. The difference between the averages of the two given sets is:

(b + c + d + e)/4 - (a+ b + c + d)/4

(e - a)/4

(a + 4 - a)/4

4/4 = 1

Answer: D

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