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## If a, b, and c are integers and ab^2/c . . .

tagged by: VJesus12

This topic has 2 expert replies and 0 member replies

### Top Member

VJesus12 Master | Next Rank: 500 Posts
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#### If a, b, and c are integers and ab^2/c . . .

Wed Nov 08, 2017 7:44 am
If a, b, and c are integers and ab^2/c is a positive even integer, which of the following must be true?

I. ab is even
II. ab > 0
III. c is even

A. I only
B. II only
C. I and II
D. I and III
E. I, II, and III

The OA is A.

Experts, may you give me some help here please? It is a hard PS question to me.

### GMAT/MBA Expert

EconomistGMATTutor GMAT Instructor
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Wed Nov 08, 2017 12:22 pm
Quote:
If a, b, and c are integers and ab^2/c is a positive even integer, which of the following must be true?

I. ab is even
II. ab > 0
III. c is even

A. I only
B. II only
C. I and II
D. I and III
E. I, II, and III

The OA is A.

Experts, may you give me some help here please? It is a hard PS question to me.
Hi VJesus12,
Let's take a look at your question.

The question says,
$$\frac{ab^2}{c}>0$$
and
$$\frac{ab^2}{c}=even$$
$$ab^2=c\times even$$
When any number is multiplied by an even number, it will result into an even number as well. Therefore,
$$ab^2=even$$
ab^2 can be even if a or b or both a and b are even.
Hence, ab will be even.
Therefore, I is true.

Let's check if II is true or not.
The question says that,
$$\frac{ab^2}{c}>0$$
Which can be true even b is negative, therefore, ab > 0 will not be true for b < 0.
Hence, II is not true.

Let's check if III is true or not.
c can not be even in all cases because the given statement can be true for c = 1 and i is not even.
Hence, III is not true.

It means only I is true.
Therefore, Option A is correct.

Hope that makes sense.
I am available if you'd like any follow up.

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### GMAT/MBA Expert

Matt@VeritasPrep GMAT Instructor
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Thu Nov 09, 2017 7:12 pm
If we've got abÂ² / c = even, then we've also got

abÂ² = c * even

That means that either a or b is even, since a * b * b = even. Once a or b is even, we know that even * any integer = even, so ab MUST be even.

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